Question

这是我的问题：我向WordPress PHP函数发出ajax请求。奇怪的是：这个响应是作为错误返回的。

但是在错误日志中，responseText是请求的数据（JSON为字符串），状态为200，statusText为“OK”。

这是请求：

  $.ajax({
      type: "GET",
      dataType: "json",
      url: ajaxurl,
      data: { action:'my_wp_function',username: settings.username, list: settings.list, hashtag: settings.hashtag, count: settings.count, exclude_replies: settings.hideReplies, lastID:settings.lastID  }
      }).done(function( res ) {

      }).error(function(err) { console.log(err); }); // err.responseText = the requested data ...

如果一切正常，为什么检测到该请求就好像发生了错误一样？

编辑，这是我要求的PHP：

<?php

require_once("twitteroauth/twitteroauth.php"); 
require_once('config.php');


if (CONSUMER_KEY === '' || CONSUMER_SECRET === '' || CONSUMER_KEY === 'CONSUMER_KEY_HERE' || CONSUMER_SECRET === 'CONSUMER_SECRET_HERE') {
    echo 'You need a consumer key and secret keys. Get one from <a href="https://dev.twitter.com/apps">dev.twitter.com/apps</a>';

    exit;
}

$username = filter_input(INPUT_GET, 'username', FILTER_SANITIZE_SPECIAL_CHARS);
$number = filter_input(INPUT_GET, 'count', FILTER_SANITIZE_NUMBER_INT);
$exclude_replies = filter_input(INPUT_GET, 'exclude_replies', FILTER_SANITIZE_SPECIAL_CHARS);
$list_slug = filter_input(INPUT_GET, 'list_slug', FILTER_SANITIZE_SPECIAL_CHARS);
$hashtag = filter_input(INPUT_GET, 'hashtag', FILTER_SANITIZE_SPECIAL_CHARS);
$lastID = filter_input(INPUT_GET, 'lastID', FILTER_SANITIZE_SPECIAL_CHARS);

if(CACHE_ENABLED) {
    // Generate cache key from query data
    $cache_key = md5(
        var_export(array($username, $number, $exclude_replies, $list_slug, $hashtag), true) . HASH_SALT
    );

    $cache_path  = dirname(__FILE__) . '/cache/';
    foreach (glob($cache_path . '*') as $file) {
        if (filemtime($file) < time() - CACHE_LIFETIME) {
            unlink($file);
        }
    }

    if(file_exists($cache_path . $cache_key)) {
        header('Content-Type: application/json');

        echo file_get_contents($cache_path . $cache_key);
        exit;
    }
}


function getConnectionWithToken($cons_key, $cons_secret, $oauth_token, $oauth_secret)
{
    $connection = new TwitterOAuth($cons_key, $cons_secret, $oauth_token, $oauth_secret);

    return $connection;
}

// Connect
$connection = getConnectionWithToken(CONSUMER_KEY, CONSUMER_SECRET, ACCESS_TOKEN, ACCESS_SECRET);

// Get Tweets
if (!empty($list_slug)) {
  $params = array(
      'owner_screen_name' => $username,
      'slug' => $list_slug,
      'per_page' => $number
  );

  $url = '/lists/statuses';
} 

else if($hashtag) {
  if($lastID){
    $params = array(
      'max_id' => $lastID,
      'count' => 100,
      'q' => '#'.$hashtag.' filter:images',
      'include_entities' => true

  );

  }
  else {
    $params = array(
      'count' => 100,
      'q' => '#'.$hashtag.' filter:images',
      'include_entities' => true

  );
  }


  $url = '/search/tweets';
} else {
  $params = array(
      'count' => $number,
      'exclude_replies' => $exclude_replies,
      'screen_name' => $username
  );

  $url = '/statuses/user_timeline';
}

// $rawTweets = $connection->get($url, $params);
// $tweets = array();
$tweets = $connection->get($url, $params);



// Return JSON Object
header('Content-Type: application/json');


$tweets = json_encode( $tweets);

if(CACHE_ENABLED) file_put_contents($cache_path . $cache_key, $tweets);

echo $tweets;

Answer 1

试试这个

$.ajax({
        url : _url,
        type : "GET",
        dataType : "JSON",
        error : function(){
            console.log("Cannot bring the core fields");
        },
        success : function (response){
                  console.info( response );
});

为什么这个Ajax请求作为错误返回？

1 个答案: