Question

您好我正在尝试将一大堆列表中的所有第一个元素加在一起，例如我有 [20，Private，266015，Some-college，10，Never-married，Sales，Own-child，Black，Male，0,0,44，United States，＆lt; = 50K]（年龄是这里的第一个元素案例20）我需要找到一个人获得＆lt; = 50K的人的平均年龄，有超过30,000个记录，如此，我怎样才能在下一个记录中添加每个年龄？这是我的代码我得到的东西，但它是不对的。任何帮助都会非常感谢。

    for row in f:
        row = row.split(", ")
        try:
            row[0] = int(row[0])
            row[2] = None
            row[3] = None
            row[4] = int(row[4])
            row[10] = int(row[10])
            row[11] = int(row[11])
            row[12] = int(row[12])
            row[13] = None

            if "?" in row:
                continue
            if row[-1] == ">50K":
                total_count +=1
                age_over_count = row[0]+row[0]
                average_age_over = age_over_count/total_count

Answer 1

如果你想找到给定row[0] row[-1]== ">50k"的平均值，你需要在循环结束后计算平均值，然后继续用你已经拥有的值添加你的age_over_count，即+ = ...

for row in f:
    row = row.split(", ")
    try:
        row[0] = int(row[0])
        row[2] = None
        row[3] = None
        row[4] = int(row[4])
        row[10] = int(row[10])
        row[11] = int(row[11])
        row[12] = int(row[12])
        row[13] = None

        if "?" in row:
            continue
        if row[-1] == ">50K":
            total_count +=1
            age_over_count += row[0]          # <- Keeps adding what you have.
average_age_over = age_over_count/total_count # <- Calculates average.

试图找到多行中元素[0]的平均值

1 个答案: