我运行程序时有以下存储过程正确执行:
$insertIntoEmployeesProcedure = "
CREATE PROCEDURE EmployeeInsert(name VARCHAR(50),password VARCHAR(50), email VARCHAR(50))
BEGIN
INSERT INTO employees(name,password,email) values(name,password,email);
END";
$returnInsertIntoEmpProc = $conn->query($insertIntoEmployeesProcedure);
if(! $returnInsertIntoEmpProc )
{
die('Could not create insert procedure: ' . $conn->error);
}
else
{
echo "Insert Procedure created successfully<br/>";
}
然后我在需要时在另一个类中调用此过程:
$insertEmp = mysqli_query($conn, "Call EmployeeInsert('$username','$password', '$email')");
$executeInsertEmp = $conn->query($insertEmp);
if(!$executeInsertEmp )
{
die('Employees not added: ' . $conn->error);
}
else
{
echo "Employees added<br/>";
}
问题是,当我执行此代码时,我收到以下错误
Employees not added: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1
我遇到的主要问题是,即使它返回此错误,记录仍会添加到数据库中,一切似乎都正常。我想我更好奇为什么我收到这个错误显然我忽略了一些东西。
答案 0 :(得分:0)
啊,我看到我做了什么,我似乎添加了一个额外的查询,这是不必要的,行:
$executeInsertEmp = $conn->query($insertEmp);
可以省略,然后在保存存储过程的变量上完成if语句中的检查。以下代码有效:
$insertEmp = mysqli_query($conn, "Call EmployeeInsert('$username','$password', '$email')");
if(!$insertEmp )
{
die('Employees not added: ' . $conn->error);
}
else
{
echo "Employees added<br/>";
}