Question

我正在调用一个返回以下数组的soap函数：

Array ( [FastAddressResult] => Array ( [IsError] => false [ErrorNumber] => 0 [ErrorMessage] => [Results] => Array ( [Address] => Array ( [Id] => 13872147.00 [OrganisationName] => [DepartmentName] => [Line1] => Methley Grove [Line2] => [Line3] => [Line4] => [Line5] => [PostTown] => Leeds [County] => West Yorkshire [Postcode] => LS7 3PA [Mailsort] => 64121 [Barcode] => [IsResidential] => false [IsSmallOrganisation] => false [IsLargeOrganisation] => false [RawData] => [GeographicData] => Array ( [GridEastM] => 0 [GridNorthM] => 0 [Objective2] => false [Transitional] => false [Longitude] => 0 [Latitude] => 0 [WGS84Longitude] => 0 [WGS84Latitude] => 0 ) ) ) )

我需要抽取以下似乎不起作用的值：

$this->adressline1 = $result->FastAddressResult->Results->Address->Line1;

Answer 1

尝试：

$this->adressline1 = $result[ "FastAddressResult" ][ "Results" ][ "Address" ][ "Line1" ];

如果$ result是一个对象，你想要使用$ result-＆gt; fastAddressResult-＆gt;等。有关PHP数组的更多信息，请查看this page。

此外，这种复杂阵列具有某些设计气味。您可以想出一种方法，使其更简单，更易读。

Answer 2

显然有人在编程类中没有注意到它们覆盖数组......

$this->adressline1 = $result['FastAddressResult']['Results']['Address']['Line1'];

或首先将数组转换为stdClass：

$data = (object) $myarray;

但是你必须为那些所有阵列做到这一点，所以没有。

Answer 3

像这样使用，

存储在一些名为$ res

的变量中的数组

   echo $res[ "FastAddressResult" ][ "Results" ][ "Address" ][ "Line1" ];

如何在PHP中从复杂数组中获取值？

3 个答案: