在PHP中，我使用Kuwamoto的类来复活我的字符串中的名词。除了一些插件，我在javascript中找不到像这个脚本一样好的东西。所以，拥有一个基于Kuwamoto等级的javascript函数会很棒。
http://kuwamoto.org/2007/12/17/improved-pluralizing-in-php-actionscript-and-ror/
答案 0 :(得分：29)
简易版（ES6）：
const maybePluralize = (count, noun, suffix = 's') =>
`${count} ${noun}${count !== 1 ? suffix : ''}`;
用法：
maybePluralize(0, 'turtle'); // 0 turtles
maybePluralize(1, 'turtle'); // 1 turtle
maybePluralize(2, 'turtle'); // 2 turtles
maybePluralize(3, 'fox', 'es'); // 3 foxes
这显然不支持所有英语边缘情况，但它适用于大多数目的
答案 1 :(得分：28)
所以，我通过在Kuwamoto的PHP课程的javascript中分享我的翻译来回答我自己的问题。
String.prototype.plural = function(revert){
var plural = {
'(quiz)$' : "$1zes",
'^(ox)$' : "$1en",
'([m|l])ouse$' : "$1ice",
'(matr|vert|ind)ix|ex$' : "$1ices",
'(x|ch|ss|sh)$' : "$1es",
'([^aeiouy]|qu)y$' : "$1ies",
'(hive)$' : "$1s",
'(?:([^f])fe|([lr])f)$' : "$1$2ves",
'(shea|lea|loa|thie)f$' : "$1ves",
'sis$' : "ses",
'([ti])um$' : "$1a",
'(tomat|potat|ech|her|vet)o$': "$1oes",
'(bu)s$' : "$1ses",
'(alias)$' : "$1es",
'(octop)us$' : "$1i",
'(ax|test)is$' : "$1es",
'(us)$' : "$1es",
'([^s]+)$' : "$1s"
};
var singular = {
'(quiz)zes$' : "$1",
'(matr)ices$' : "$1ix",
'(vert|ind)ices$' : "$1ex",
'^(ox)en$' : "$1",
'(alias)es$' : "$1",
'(octop|vir)i$' : "$1us",
'(cris|ax|test)es$' : "$1is",
'(shoe)s$' : "$1",
'(o)es$' : "$1",
'(bus)es$' : "$1",
'([m|l])ice$' : "$1ouse",
'(x|ch|ss|sh)es$' : "$1",
'(m)ovies$' : "$1ovie",
'(s)eries$' : "$1eries",
'([^aeiouy]|qu)ies$' : "$1y",
'([lr])ves$' : "$1f",
'(tive)s$' : "$1",
'(hive)s$' : "$1",
'(li|wi|kni)ves$' : "$1fe",
'(shea|loa|lea|thie)ves$': "$1f",
'(^analy)ses$' : "$1sis",
'((a)naly|(b)a|(d)iagno|(p)arenthe|(p)rogno|(s)ynop|(t)he)ses$': "$1$2sis",
'([ti])a$' : "$1um",
'(n)ews$' : "$1ews",
'(h|bl)ouses$' : "$1ouse",
'(corpse)s$' : "$1",
'(us)es$' : "$1",
's$' : ""
};
var irregular = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
};
var uncountable = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment'
];
// save some time in the case that singular and plural are the same
if(uncountable.indexOf(this.toLowerCase()) >= 0)
return this;
// check for irregular forms
for(word in irregular){
if(revert){
var pattern = new RegExp(irregular[word]+'$', 'i');
var replace = word;
} else{ var pattern = new RegExp(word+'$', 'i');
var replace = irregular[word];
}
if(pattern.test(this))
return this.replace(pattern, replace);
}
if(revert) var array = singular;
else var array = plural;
// check for matches using regular expressions
for(reg in array){
var pattern = new RegExp(reg, 'i');
if(pattern.test(this))
return this.replace(pattern, array[reg]);
}
return this;
}
易于使用：
alert("page".plural()); // return plural form => pages
alert("mouse".plural()); // return plural form => mice
alert("women".plural(true)); // return singular form => woman
<强> DEMO
答案 2 :(得分：25)
这是一个名为Pluralize的小型图书馆，在npm和bower中打包。
这就是它的用法：
import Pluralize from 'pluralize';
Pluralize( 'Towel', 42 ); // "Towels"
Pluralize( 'Towel', 42, true ); // "42 Towels"
你可以在这里得到它：
答案 3 :(得分：6)
取自我的博客：https://sergiotapia.me/pluralizing-strings-in-javascript-es6-b5d4d651d403
您可以使用pluralize库。
NPM:
npm install pluralize --save
Yarn:
yarn add pluralize
无论您想使用lib，都可以轻松地使用它。
var pluralize = require('pluralize')
我喜欢将它添加到window对象中，所以我可以在需要的地方调用pluralize（）。在我的application.js根文件中：
window.pluralize = require('pluralize')
然后你可以在任何地方使用它，React组件，或者只是简单的Javascript：
<span className="pull-left">
{`${item.score} ${pluralize('point', item.score)}`}
</span>
console.log(pluralize('point', item.score))
答案 4 :(得分：5)
我使用这个简单的内联语句
const number = 2;
const string = `${number} trutle${number === 1 ? "" : "s"}`; //this one
console.log(string)
答案 5 :(得分：3)
来自ECMA的新intl API规范将提供复数规则函数， https://github.com/tc39/proposal-intl-plural-rules
这是今天可以使用的填充物https://github.com/eemeli/IntlPluralRules
答案 6 :(得分：1)
我创建了一个非常简单的库，可用于JavaScript中的单词复数化。它透明地将CLDR数据库用于多个语言环境，因此它几乎支持您要使用的任何语言。它的API非常简约，集成非常简单。它被称为Numerous。
我还写了一篇小介绍文章：«How to pluralize any word in different languages using JavaScript?»。
随意在您的项目中使用它。我也很高兴收到您的反馈意见。
答案 7 :(得分：1)
function pluralize( /* n, [ n2, n3, ... ] str */ ) {
var n = Array.prototype.slice.call( arguments ) ;
var str = n.pop(), iMax = n.length - 1, i = -1, j ;
str = str.replace( /\$\$|\$(\d+)/g,
function( m, p1 ) { return m == '$$' ? '$' : n[+p1-1] }
) ;
return str.replace( /[(](.*?)([+-])(\d*)(?:,([^,)]*))?(?:,([^)]*))?[)]/g,
function( match, one, sign, abs, not1, zero ) {
// if abs, use indicated element in the array of numbers
// instead of using the next element in sequence
abs ? ( j = +abs - 1 ) : ( i < iMax && i++, j = i ) ;
if ( zero != undefined && n[j] == 0 ) return zero ;
return ( n[j] != 1 ) == ( sign == '+' ) ? ( not1 || 's' ) : one ;
}
) ;
}
console.log( pluralize( 1, 'the cat(+) live(-) outside' ) ) ;
// the cat lives outside
console.log( pluralize( 2, 'the child(+,ren) (is+,are) inside' ) ) ;
// the children are inside
console.log( pluralize( 0, '$1 dog(+), ($1+,$1,no) dog(+), ($1+,$1,no) dog(+,,)' ) ) ;
// 0 dogs, no dogs, no dog
console.log( pluralize( 100, 1, '$1 penn(y+,ies) make(-1) $$$2' ) ) ;
// 100 pennies make $1
console.log( pluralize( 1, 0.01, '$1 penn(y+,ies) make(-1) $$$2' ) ) ;
// 1 penny makes $0.01
答案 8 :(得分：1)
使用@sarink的答案，我创建了一个函数，该函数使用键值对数据创建键并对键进行复数操作。这是代码段：
// Function to create a string from given key value pairs and pluralize keys
const stringPluralize = function(data){
var suffix = 's';
var str = '';
$.each(data, function(key, val){
if(str != ''){
str += val>0 ? ` and ${val} ${key}${val !== 1 ? suffix : ''}` : '';
}
else{
str = val>0 ? `${val} ${key}${val !== 1 ? suffix : ''}` : '';
}
});
return str;
}
var leftDays = '1';
var leftHours = '12';
var str = stringPluralize({day:leftDays, hour:leftHours});
console.log(str) // Gives 1 day and 12 hours
答案 9 :(得分：0)
基于@pmrotule答案，带有一些打字稿魔术和对不可数数组的一些补充。我在这里添加了复数和单数函数。
复数形式：
/**
* Returns the plural of an English word.
*
* @export
* @param {string} word
* @param {number} [amount]
* @returns {string}
*/
export function plural(word: string, amount?: number): string {
if (amount !== undefined && amount === 1) {
return word
}
const plural: { [key: string]: string } = {
'(quiz)$' : "$1zes",
'^(ox)$' : "$1en",
'([m|l])ouse$' : "$1ice",
'(matr|vert|ind)ix|ex$' : "$1ices",
'(x|ch|ss|sh)$' : "$1es",
'([^aeiouy]|qu)y$' : "$1ies",
'(hive)$' : "$1s",
'(?:([^f])fe|([lr])f)$' : "$1$2ves",
'(shea|lea|loa|thie)f$' : "$1ves",
'sis$' : "ses",
'([ti])um$' : "$1a",
'(tomat|potat|ech|her|vet)o$': "$1oes",
'(bu)s$' : "$1ses",
'(alias)$' : "$1es",
'(octop)us$' : "$1i",
'(ax|test)is$' : "$1es",
'(us)$' : "$1es",
'([^s]+)$' : "$1s"
}
const irregular: { [key: string]: string } = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
}
const uncountable: string[] = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment',
'bison',
'cod',
'offspring',
'pike',
'salmon',
'shrimp',
'swine',
'trout',
'aircraft',
'hovercraft',
'spacecraft',
'sugar',
'tuna',
'you',
'wood'
]
// save some time in the case that singular and plural are the same
if (uncountable.indexOf(word.toLowerCase()) >= 0) {
return word
}
// check for irregular forms
for (const w in irregular) {
const pattern = new RegExp(`${w}$`, 'i')
const replace = irregular[w]
if (pattern.test(word)) {
return word.replace(pattern, replace)
}
}
// check for matches using regular expressions
for (const reg in plural) {
const pattern = new RegExp(reg, 'i')
if (pattern.test(word)) {
return word.replace(pattern, plural[reg])
}
}
return word
}
单数版本：
/**
* Returns the singular of an English word.
*
* @export
* @param {string} word
* @param {number} [amount]
* @returns {string}
*/
export function singular(word: string, amount?: number): string {
if (amount !== undefined && amount !== 1) {
return word
}
const singular: { [key: string]: string } = {
'(quiz)zes$' : "$1",
'(matr)ices$' : "$1ix",
'(vert|ind)ices$' : "$1ex",
'^(ox)en$' : "$1",
'(alias)es$' : "$1",
'(octop|vir)i$' : "$1us",
'(cris|ax|test)es$' : "$1is",
'(shoe)s$' : "$1",
'(o)es$' : "$1",
'(bus)es$' : "$1",
'([m|l])ice$' : "$1ouse",
'(x|ch|ss|sh)es$' : "$1",
'(m)ovies$' : "$1ovie",
'(s)eries$' : "$1eries",
'([^aeiouy]|qu)ies$' : "$1y",
'([lr])ves$' : "$1f",
'(tive)s$' : "$1",
'(hive)s$' : "$1",
'(li|wi|kni)ves$' : "$1fe",
'(shea|loa|lea|thie)ves$': "$1f",
'(^analy)ses$' : "$1sis",
'((a)naly|(b)a|(d)iagno|(p)arenthe|(p)rogno|(s)ynop|(t)he)ses$': "$1$2sis",
'([ti])a$' : "$1um",
'(n)ews$' : "$1ews",
'(h|bl)ouses$' : "$1ouse",
'(corpse)s$' : "$1",
'(us)es$' : "$1",
's$' : ""
}
const irregular: { [key: string]: string } = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
}
const uncountable: string[] = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment',
'bison',
'cod',
'offspring',
'pike',
'salmon',
'shrimp',
'swine',
'trout',
'aircraft',
'hovercraft',
'spacecraft',
'sugar',
'tuna',
'you',
'wood'
]
// save some time in the case that singular and plural are the same
if (uncountable.indexOf(word.toLowerCase()) >= 0) {
return word
}
// check for irregular forms
for (const w in irregular) {
const pattern = new RegExp(`${irregular[w]}$`, 'i')
const replace = w
if (pattern.test(word)) {
return word.replace(pattern, replace)
}
}
// check for matches using regular expressions
for (const reg in singular) {
const pattern = new RegExp(reg, 'i')
if (pattern.test(word)) {
return word.replace(pattern, singular[reg])
}
}
return word
}
答案 10 :(得分：0)
要提供一个简单易读的选项（ES6）：
/usr/local/mysql/bin如果您提供类似export function pluralizeAndStringify(value, word, suffix = 's'){
if (value == 1){
return value + ' ' + word;
}
else {
return value + ' ' + word + suffix;
}
}
的信息，则会得到“ 5条狗”作为输出。