Question

如何等待所有AngularJS＆＃39; $timeouts已完成？

for (var i = 0; i < 1000; i++) {
   $timeout(function () {
      //do sth
   }, 100);
};

//then do something else is all $timeouts are done

Answer 1

您可以使用超时返回的承诺，并使用$q.all（注入$q）的组合来实现这一目标。

实施例： -

var promises = [];

for (var i = 0; i < 1000; i++) {
  promises.push(performTask(i)); //push promise to the array
}


//If in your real case i is actually an array of something then you can 
//just simplify it to $q.all(myArrayOfInputs.map(performTask)).then(...)

$q.all(promises).then(performDoneTask); //use q.all to wait for all promises to be fulfilled.

//Method that does something once all the timeouts are completed
function performDoneTask(){

}

//Method that does something with i and returns a promise from the timeout
function performTask(i){ 
  return $timeout(function () {
      //do sth
   }, 100);
}

AngularJS等到很多$ timeout完成

1 个答案: