Question

将可选块传递给Swift中的函数的正确语法是什么？

Answer 1

尽管不像Objective-C块语法那样难以记住，但它并不明显。在此示例中，notConnected参数是可选的：

    func whenConnected(block: Void -> Void, notConnected: ((Void) -> Void)?, showErrorMessage: Bool) -> Void {

        let connected = Reachability.isConnectedToNetwork()

        if connected {
            block()
        } else {
            notConnected?()
        }

        if showErrorMessage {
            // your error handling //
        }
    }

Answer 2

我找到了它的示例（请参阅下面的链接）并将其修改为在我的项目中使用typealias。

斯威夫特3：

import Foundation

typealias CompletionBlock = (NSError?) -> Void
var completionBlock: CompletionBlock?

// a function declaration w/ optional closure param and default value
func doSomething(completion: CompletionBlock? = nil) {
    // assign to the property, to call back out of this function's scope
    completionBlock = completion
    // ...
    // optional closure callback
    completionBlock?(nil)
    // ...
}

func doSomethingElse() {
    // 1. pass optional (nil) closure to a function
    doSomething()

    // 2. pass optional (non-nil) closure to a function
    doSomething(completion: { (error) -> Void in
        print("error: \(error)")
    })
}

来源：Optional trailing closures in Swift

注意：因为completion被声明为可选闭包，所以它总是转义。更多相关内容：Optional Non-Escaping Closures

Answer 3

typealias ServiceResponse =（AnyObject？，String？）->无效

功能请求（onCompletion：@转义ServiceResponse）{ 你需要写的东西 }

将可选块或闭包传递给Swift中的函数

3 个答案: