Question

我有一个用户名和密码验证查询。我可以进行现场验证，但不能进行LOGIN验证。

下面给出了使用的编码。未显示登录成功或失败的警报我的意思是检查用户名和密码是否未发生匹配/不匹配。正在使用的函数没有到Checkpassword.php来提供消息/警报。你能告诉你如何解决这个问题。

<script>
    $(document).ready(function () {
        //* validation
        $('#login').validate({
            onkeyup: false,
            errorClass: 'error',
            validClass: 'valid',
            rules: {
                user_email: {
                    required: true,
                    email: true
                },
                user_pass: {
                    required: true,
                    minlength: 6
                }
            },
            messages: {
                user_email: {
                    required: 'Please enter your email ID',
                    email: 'Please enter a valid email ID'
                },
                user_pass: {
                    required: 'Please enter your password',
                    minlength: 'Please enter at least 6 characters.'
                }
            },
            highlight: function (element) {
                $(element).closest('.f_er').addClass("f_error");

            },
            unhighlight: function (element) {
                $(element).closest('.f_er').removeClass("f_error");

            }
        });
    });

    /* Login validation */
    $(document).on('click', '#login1', function () {
        $('#login').validate();
        var validate_login = $('#login').valid();
        if (validate_login === true)
        {
            var post_data = $('#login').serialize();
            $.ajax({
                type: "POST",
                url: "checkpassword.php",
                data: post_data,
                success: function (msg) {
                    var resultarr = msg;
                    // $(".page-loader").remove();
                    var success_msg = $.trim(resultarr[0]);
                    if (success_msg === "SUCCESS")
                    {
                        //var login_token = resultarr[1];
                        // $.cookie("covogue_login_token", login_token, {
                        //    expires: 30
                        //});
                        window.location.href = "blog.php";
                    }
                    if (success_msg === "FAIL")
                    {
                        $("#error_li").show();
                        $("#login_result").text('Please enter a valid email ID and password.');
                        alert("Please enter a valid email ID and password.");
                    }
                },
                error: function () {
                    //$(".page-loader").remove();
                    // sticky_notifications('Oops!! Try that again in a few moments.',{type: "error"});
                    alert("Try Again");
                }
            });
        } else {
            alert("Try Again1");
        }
    });
</script>

<div class="user_login">
    <form method="post" id="login" name="login" class="f_er">
        <!--<label><div id="error" style="color:red; text-align: center;"></div></label>-->
        <label>Email</label>
        <input type="text" name="user_email" id="user_email" autofocus/> 
        <br />

        <label>Password</label>
        <input type="password" name="user_pass" id="user_pass"/>
        <br />
        <li style="display:none;" id="error_li"><span id="login_result" class="error_color"></span></li>
        <div class="action_btns">
            <div class="one_half"><a href="#" class="btn back_btn"><i class="fa fa-angle-double-left"></i> Back</a></div>
            <div class="one_half last"><button type="button" name="login1" id="login1" class="btn btn_red">Login</button></div>
        </div>
    </form>
    <a href="forgot_password.php" class="forgot_password">Forgot password?</a>
</div>

checkpassword.php

<?php
    include 'admin/config.php';
    $username = $_POST['user_email'];
    $password = $_POST['user_pass'];
    $check = mysqli_query($con,"select username,
    password from blog_login where username = '$username' and password = '$passwod'");
    $count = mysqli_num_rows($check);

    if( $count == '1' ){
        echo "SUCCESS";
    } else {
        echo "FAIL";
    }
?>

Answer 1

select username,password from blog_login where username = '$username' and password = '$passwod'

在PASSWORD附近的查询中，这只是一个拼写错误..你给了＆＃34; passwod＆＃34;它应该是＆＃34; $ password＆＃34; ..

$password = $_POST['user_pass'];

所以，

select username,password from blog_login where username = '$username' and password = '$password'

Answer 2

checkpassword.php

中有错误

$check = mysqli_query($con,"select username,
    password from blog_login where username = '$username' and password = '$passwod'")

必须是$password而不是$passwod ...

登录表单验证问题

2 个答案: