Question

所以这是错误：

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: idnum

Filename: models/model_teacher.php

Line Number: 8

这是我的控制者：

 public function teacher(){

   $this->load->model('model_teacher');

   $data['result'] = $this->model_teacher->scoreboard();
   $this->load->view('teacher/teacher', $data);
  }

和我的模特：

 class Model_teacher extends CI_Model {

    public function scoreboard() {

        $this->db->where('login_id', $this->input->post('idnum'));
        $query = $this->db->query("SELECT * FROM teacher WHERE login_id = '".$idnum."'");
        return $query->result();

        }
}

和视图：

<?php
  foreach ($result as $row) {
            echo $row->login_id."<br>";
            echo $row->lname."<br>";
        }
?>

并且不知道这段代码有什么问题。请耐心等待我，我仍然是使用codeigniter的新手。多谢你们。

Answer 1

更改如下：

在控制器

中

 public function teacher(){
   $this->load->model('model_teacher');
   $idNum = $this->input->post('idnum');
   $data['result'] = $this->model_teacher->scoreboard($idNum);
   $this->load->view('teacher/teacher', $data);
  }

在模型中

   public function scoreboard($idNum) {
      $this->db->where('login_id', $idNum);
      $query = $this->db->query("SELECT * FROM teacher WHERE login_id = '".$idnum."'");
      return $query->result();
   }

Answer 2

如果将它从控制器传递给模型

会更好

$id = $this->input->post('idnum');
$data['result'] = $this->model_teacher->scoreboard($id);

和型号： -

public function scoreboard($id) {
  //$this->db->where('login_id', $id);
  $query = $this->db->query("SELECT * FROM teacher WHERE login_id = '".$id."'");
  return $query->result();
}

此外，您还无法定义任何地方$idnum，因此会出现通知

Answer 3

你不能直接进入模型，你必须首先进入控制器的控制器

public function teacher(){ $id = $this->input->post('idnum'); $this->load->model('model_teacher'); $data['result'] = $this->model_teacher->scoreboard($id); $this->load->view('teacher/teacher', $data); }

<强>模型`

public function scoreboard($idnum) { $query = $this->db->query("SELECT * FROM teacher WHERE login_id = '".$idnum."'"); return $query->result(); }`

这是您可以使用的代码

codeigniter中的模型将无法识别ID号

3 个答案: