Question

我有一个查询，它会返回客户拨打电话的结果以及为客户提供的一些建议等等... ...按日期分组

但现在我想找到我尝试按lead_id和cuncat(lead_id,timecreatredFormat)进行分组的客户数仍然存在数据不匹配

以下是我尝试的查询

    select 
    sum(t.enquiry_cnt),
    sum(t.suggested_cnt),
    sum(t.tot_cnt)

from
    (select 

        case
                when source = 1 then 1
                else 0
            end enquiry_cnt,

            case
                when source = 6 then 1
                else 0
            end suggested_cnt,
            case
                when (source = 1 || source = 6) then 1
                else 0
            end tot_cnt,
             date_format(timecreated, '%d-%b-%Y') created_time,
            lead_id,timecreated
    from
        mg_lead_suggested_listing  group by  concat(created_time,lead_id)   ) t
group by  t.created_time
order by t.timecreated desc
limit 10;

提前致谢

Answer 1

检查以下查询是否正确。我添加了COUNT（DISTINCT t.lead_id）来获取客户数量。

DECLARE @TEMP TABLE
(
    [source] INT,
    lead_id INT,
    timecreated DATETIME
)

INSERT INTO @TEMP VALUES (1,1,GETDATE())
INSERT INTO @TEMP VALUES (6,1,GETDATE())
INSERT INTO @TEMP VALUES (6,1,GETDATE())
INSERT INTO @TEMP VALUES (1,2,DATEADD(d,-1,GETDATE()))
INSERT INTO @TEMP VALUES (1,1,DATEADD(d,-1,GETDATE()))
INSERT INTO @TEMP VALUES (1,1,DATEADD(d,-1,GETDATE()))


SELECT
    CAST(t.timecreated AS DATE) [date],
     SUM(t.enquiry_cnt) enquiry_cnt,
    (SELECT COUNT(DISTINCT lead_id) FROM @TEMP WHERE CAST(timecreated AS DATE) = CAST(t.timecreated AS DATE) AND [source] = 1) as lead_enquiry_cnt,
    SUM(t.suggested_cnt) suggested_cnt,
    (SELECT COUNT(DISTINCT lead_id) FROM @TEMP WHERE CAST(timecreated AS DATE) = CAST(t.timecreated AS DATE) AND [source] = 6) as lead_suggested_cnt,
    SUM(t.tot_cnt) tot_cnt,
    COUNT(t.lead_id) as lead_cnt
FROM
(
    SELECT 
        CASE 
            WHEN [source] = 1 THEN 1
            ELSE 0
        END enquiry_cnt,
        CASE
            WHEN [source] = 6 THEN 1
            ELSE 0
        END suggested_cnt,
        CASE
            WHEN ([source] = 1 OR [source] = 6) THEN 1
            ELSE 0
        END tot_cnt,
        lead_id,
        timecreated
    FROM
        @TEMP
    ) AS t
group by  
    CAST(t.timecreated AS DATE)
order by 
    [date] desc

SQL：使用group by concat（）

1 个答案: