Question

我是Prolog的全新手。我试图找出一个问题，我需要检查边缘之间是否存在路径。我完成了非循环图代码循环我的代码将无限循环。

path(Start, End) :- edge(Start, End).
path(Start, End) :- edge(Start, Z), path(Z, End).

我需要通过定义一个新谓词来处理这种情况： new_path（开始，结束，路径）这应该消除无限循环。请让我知道如何处理它。

Answer 1

尝试

path(Start, End) :-
   closure(edge, Start, End).

使用this definition for closure/3

Answer 2

您需要使用prolog列表作为LIFO堆栈，随时跟踪您访问过的节点。这些方面的东西：

path( A , Z , P ) :-           % to find a path from A to Z
  traverse( A , Z , [] , P ) , % take a walk, visiting A to see if we can get to Z, seeding the visited list with the empty string.
  reverse(P,Path)              % once we find a path, let's reverse it, since it's in LIFO order.
  .                            % That's all there is to it, really.

traverse( Z , Z , V , [Z|V] )     % if current node is the destination node, we've arrived.
  .                               % - just push the destination vertice onto the visited list and unify that with the path
traverse( A , Z , V , P ) :-      % Otherwise...
  edge( A , Z ) ,                 % - if the current node is directly connected to the destination node,
  traverse( Z , Z , [A|V] , P)    % - go visit the destination, marking the current node as visited
  .                               %
traverse( A, Z , V , P ) :-       % Otherwise...
  A \= Z,
  edge( A , B ) ,                 % - if the current node is connected to a node
  B \= Z ,                        % - that is not the destination node, and
  unvisited([A|V],B) ,            % - we have not yet visited that node,
  traverse( B , Z , [A|V] , P )   % - go visit the intermediate node, marking the current node as visited.
  .                               % Easy!

unvisited( []    , _ ) .                   % We succeed if the visited list is empty.
unvisited( [A|_] , A ) :- ! , fail .       % We fail deterministically if we find the node in the visited list.
unvisited( [_|L] , A ) :- unvisited(L,A) . % otherwise, we keep looking.

Prolog图路径搜索循环路径

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