Question

我有一个视图，我正在获取有限制的约会列表..

def HospitalAppointmentView(request, pk, username, hdpk):
todays_appointments = DoctorAppointment.objects.filter(hospital__id=pk, doctor__id=hdpk, appointment_date=today).order_by("-appointment_date")[:5]

return render_to_response('doctor_appointment_list.html', {"todays_appointments": todays_appointments}, context_instance=RequestContext(request))

在我的模板中：

{% for appointment in todays_appointments %}
    <h3>{{appointment.doctor.username}}<h3>
    <tr>
    <td>{{appointment.appointment_date}}</td>
    <td>{{appointment.first_name}} &nbsp;{{appointment.middle_name}} &nbsp; {{appointment.last_name}}</td>
    <td>{{appointment.user}}</td></tr>
    <a href="{% url "all_appointments" appointment.hospital.id appointment.doctor.id%}">
    See All</a>

{% endfor %}

正确显示5个约会，除了“全部查看”重复5次，我想将医生的用户名作为标题，并且还要打印5次。

当我点击“全部查看”时，我想重定向到可以看到所有约会的页面。像：

def HospitalAppointmentView(request, pk, username, hdpk):
todays_appointments = DoctorAppointment.objects.filter(hospital__id=pk, doctor__id=hdpk, appointment_date=today).order_by("-appointment_date")

return render_to_response('all_appointment.html', {"todays_appointments": todays_appointments}, context_instance=RequestContext(request))

如果我在for循环之外写“See All”，我就无法访问hospital.id和doctor.id并且在循环内部我得到“全部看见”5次，同样符合{{appointment.doctor.username} }。

如何在不打印的情况下重定向5次，并且网址中需要所有信息并且{{appointment.doctor.username}}被打印一次？

Answer 1

您可以使用{{forloop.first}}，第一次迭代就是如此。喜欢......

{% for appointment in todays_appointments %}

    {% if forloop.first %}
        <h3>{{appointment.doctor.username}}<h3>
    {%endif%}

    ...
{%endfor%}

Answer 2

{{todays_appointments.0.doctor.username}}

和你的正常循环。

{% for appointment in todays_appointments %}
 ....
{% endfor %}

但是罗恩的回答更明智

django打印循环值只有一次

2 个答案: