Question

我有以下代码：

#include<stdio.h>
void main()
{
  int a = -1, b = 1, c = 0, i, n, sum = 0 ;
  printf("Enter the limit : ") ;
  scanf("%d", &n) ;
  printf("\nThe fibonacci series is :") ;
  for(i = 1 ; i <= n ; i++)
  {
   c = a + b ;
   printf("%d-", c) ;
   sum = sum + c ;
   a = b ;
   b = c ;
  }
  printf("\nThe sum of the fibonacci series is : %d", sum) ;
  printf("\n");
}

现在我需要找到使总和大于7位的系列术语，我该怎么做？ P.S我是C的新手，对不起我的英语。

Answer 1

如果您想获得七位数的第一个总和，请将您的阈值设置为一百万，也称为1e6 = 10**6 = 1000000。请注意，1000000中有七位数字。

如果您希望总和超过七位数，请将阈值设置为一千万。这个数字有八位数。

以下代码可以解决问题。请注意，我们有一个for循环而不是while循环，它会在总和小于阈值的情况下继续迭代。

# include <stdio.h>

int main() {
  int previous, current = 0, next = 1,
      sum = current, threshold;
  printf("Enter the threshold: ") ;
  scanf("%d", &threshold) ;
  printf("Fibonacci series: %d", current) ;
  while (sum < threshold) {
    previous = current;
    current = next;
    next = previous + current;
    printf(" + %d", current) ;
    sum += current;
  }
  printf(" = %d\n", sum);
  return 0;
}

Answer 2

#include<stdio.h>
void main()
{
 int a = -1, b = 1, c = 0, i, n, term1, term2;
 long sum = 0;
 printf("Enter the limit : ");
 scanf("%d", &n);
 printf("\nThe fibonacci series is :");
 for(i = 1 ; i <= n ; i++)
 {
  c = a + b ;
  printf("%d \n", c) ;
  sum = sum + c ;
  if(sum >= 1000000){
  term1 = a;
  term2 = b;
  break;
  }
a = b ;
b = c ;
}

printf("\nThe sum of the fibonacci series is : %ld", sum);
printf("\n terms are %d and %d", term1, term2);
printf("\n");
}

当程序找到使得总和超过7位的正确术语时，它会从循环中断。希望我理解你的意思。

Answer 3

尽可能少地更改代码：

# include <stdio.h>
int main(int argc, char ** argv)
{
    int a = -1, b = 1, c = 0, i = 1, n = 0, sum = 0 ;
    printf("\nThe fibonacci series is :") ;
    while (sum <= 10000000)
    {
        c = a + b ;
        printf("%d-", c) ;
        sum = sum + c ;
        a = b ;
        b = c ;
        n = i;
        i++;
    }
    printf("\nThe sum of the fibonacci series is : %d", sum) ;
    printf("\nThe term is %d the value is %d", n , c);
    printf("\n");
    return 0;
}

Answer 4

您可以执行以下操作（您必须在顶部（第4行）声明number和found = 0）：

    if(sum >= 1000000 && !found) {
        specialNumber = fibonacci;
        found = 1;
    }

因此它检查总和是否大于7位数！如果是，那么最后一个斐波那契数字就是你搜索的数字，这是使总和大于7位数的数字！并且发现只有第一个数字被分配给specialNumber。

所以你的程序看起来应该是这样的：

#include <stdio.h>

int main() {

    int count, sum, specialNumber, fibonacci, numberOne, numberTow, found;
    sum = 0, fibonacci = 0, numberOne = -1, numberTow = 1, found = 0;
    int n;

    printf("Enter the limit :\n>") ;
    scanf("%d", &n) ;

    printf("\nThe fibonacci series is :") ;
    for(count = 1 ; count <= n ; count++) {
        fibonacci = numberOne + numberTow;
        printf("\n%d", fibonacci);
        sum += fibonacci;
        if(sum >= 1000000 && !found) {
            specialNumber = fibonacci;
            found = 1;
        }

        numberOne = numberTow;
        numberTow = fibonacci;
    }

    printf("\nThe sum of the fibonacci series is : %d\n", sum);
    printf("%d makes the sum bigger than 7 digits", specialNumber);

  return 0;

}

斐波那契数列和

4 个答案: