Question

我有一个很多行的文件。格式如下，

//many lines of normal text

      00.0000125  1319280   9.2  The Shawshank Redemption (1994)
//lines of text
      0000011111      59   6.8  "$#*! My Dad Says" (2010) {You Can't Handle the Truce (#1.10)}
      1...101002      17   6.6  "$1,000,000 Chance of a Lifetime" (1986)

我想将数据拆分为列1...101002,17,6.6,"$1,000,000 Chance of a Lifetime" (1986)

我尝试的程序是，

import re
f = open("E:/file.list");
reg = re.compile('[+ ].{10,}[+ ][+0-9].{3,}[+ ]')
for each in f:
if reg.match(each):
    print each
    print reg.split(each)

我不知道要使用的正则表达式是否正确答案。

Answer 1

在这种情况下，匹配更容易，而不是拆分。

^\s*(\S+)\s+(\S+)\s+(\S+)\s+(.*)$

试试这个。看看演示。

http://regex101.com/r/oE6jJ1/47

import re
p = re.compile(ur'^\s*(\S+)\s+(\S+)\s+(\S+)\s+(.*)$', re.IGNORECASE | re.MULTILINE)
test_str = u"00.0000125 1319280 9.2 The Shawshank Redemption (1994)\n\n 0000011111 59 6.8 \"$#*! My Dad Says\" (2010) {You Can't Handle the Truce (#1.10)}\n 1...101002 17 6.6 \"$1,000,000 Chance of a Lifetime\" (1986)"

re.findall(p, test_str)

Answer 2

>>> text="""0000011111      59   6.8  "$#*! My Dad Says" (2010) {You Can't Handle the Truce (#1.10)}
...       1...101002      17   6.6  "$1,000,000 Chance of a Lifetime" (1986)"""
>>> re.findall(r'([0-9\.]+)\s*([0-9]+)\s*([0-9\.]+)\s*(".*")',text)
[('0000011111', '59', '6.8', '"$#*! My Dad Says"'), ('1...101002', '17', '6.6', '"$1,000,000 Chance of a Lifetime"')]

Answer 3

我改变了RegEx模式。

import re
f = open("file.txt");

reg = re.compile(r"      (.{10}) *(\d*) *(\d*\.\d*) (.*)")
for each in f:
    if reg.match(each):
        print each
        print reg.split(each)

Answer 4

像

这样的东西

>>> str='1...101002      17   6.6  "$1,000,000 Chance of a Lifetime" (1986)'
>>> re.findall(r'^([^ ]+)\s+([^ ]+)\s+([^ ]+)\s+(.*)', str)
[('1...101002', '17', '6.6', '"$1,000,000 Chance of a Lifetime" (1986)')]

Answer 5

首先按split()函数拆分行，然后将拆分列表（使用itertools.islice()）从列表前导切换到括号中的数字（if re.match(r'$\d+$',j)）：< / p>

>>> s="""0000011111      59   6.8  "$#*! My Dad Says" (2010) {You Can't Handle the Truce (#1.10)}"""
>>> s.split()
['0000011111', '59', '6.8', '"$#*!', 'My', 'Dad', 'Says"', '(2010)', '{You', "Can't", 'Handle', 'the', 'Truce', '(#1.10)}']
>>> l=s.split()
>>> [list(islice(l,0,i+1)) for i,j in enumerate(l) if re.match(r'\(\d+\)',j)]
[['0000011111', '59', '6.8', '"$#*!', 'My', 'Dad', 'Says"', '(2010)']]

如果您的行在列表中（使用readlines()读取文件）：

>>> lines = ["""00.0000125  1319280   9.2  The Shawshank Redemption (1994)""","""0000011111      59   6.8  "$#*! My Dad Says" (2010) {You Can't Handle the Truce (#1.10)}""", """1...101002      17   6.6  "$1,000,000 Chance of a Lifetime" (1986)"""]

>>> [list(islice(line.split(),0,i+1)) for line in lines for i,j in enumerate(line.split()) if re.match(r'\(\d+\)',j)]
[['00.0000125', '1319280', '9.2', 'The', 'Shawshank', 'Redemption', '(1994)'], ['0000011111', '59', '6.8', '"$#*!', 'My', 'Dad', 'Says"', '(2010)'], ['1...101002', '17', '6.6', '"$1,000,000', 'Chance', 'of', 'a', 'Lifetime"', '(1986)']]

在python中使用正则表达式拆分数据

5 个答案: