字典访问键和值

时间:2014-11-26 23:28:11

标签: python-3.x

所以我的字典看起来像这样:

  

{'wandered':[YearCount(year = 2005,count = 83769),YearCount(year = 2006,count = 87688),YearCount(year = 2007,count = 108634),YearCount(year = 2008,count = 171015)],'request':[YearCount(year = 2005,count = 646179),YearCount(year = 2006,count = 677820),YearCount(year = 2007,count = 697645),YearCount(year = 2008,count = 795265)],'机场':[YearCount(年= 2007,计数= 175702),YearCount(年= 2008,计数= 173294)]}

值保存在包含年份和计数的YearCount对象中。

如何访问每个密钥中的每个字母,例如“徘徊”,?我正在尝试创建一个列表,其中包含按总计缩放的字母的相对频率 字母按字母顺序排列。

实施例。

[0.03104758705050717, 0.0, 0.0, 0.03500991824543893, 0.2536276129665047, 0.0, 0.
0, 0.0, 0.013542627927787708, 0.0, 0.0, 0.0, 0.0, 0.017504959122719464, 0.013542
627927787708, 0.013542627927787708, 0.10930884736053291, 0.15389906233882777, 0.
10930884736053291, 0.12285147528832062, 0.10930884736053291, 0.0, 0.017504959122
719464, 0.0, 0.0, 0.0]

1 个答案:

答案 0 :(得分:0)

你可以这样做:

for key in d:
    for letter in key:
        print(key, letter)