Question

我正在尝试制作一个返回布尔值的程序，无论矩阵是否为魔方。我尝试在我学院的网站上提交此代码，但它返回“错误答案”。我看不出它有什么问题。你能救我吗？

def magico(xs):

    #print(soma(xs),soma2(xs),diag(xs))
    if(soma(xs) == soma2(xs) == diag(xs) != -1 ):
        return True
    else:
        return False

def soma(xs):

    sant = 0
    s = 0
    for i in range(len(xs)):
        if(s != sant):
            return -1
        s = 0
        for j in range(len(xs)):
            s = s + int(xs[i][j])
        sant = s
    return s

def soma2(xs):

    s = 0
    sant = 0
    for j in range(len(xs)):
        if(s != sant):
            return -1
        s = 0
        for i in range(len(xs)):
            s = s + int(xs[j][i])
        sant = s
    return s

def diag(xs):

    s = 0
    for i in range(len(xs)):
        s = s + int(xs[i][i])
    t = 0
    for i in range(len(xs)):
        t = t + int(xs[i][len(xs) - 1 - i])
    if(s == t):
        return s
    else:
        return -1

Answer 1

伪代码

magic = true
answer = sum(square)/n_rows(square)
for r in rows(square):
    if sum(r) not equal to answer
        magic = false
for c in columns(square):
    if sum(c) not equal to answer
        magic = false
d1 = principal_diagonal(square)
d2 = secondary_diagonal(square)
if sum(d1) or sum(d2) not equal to answer
    magic = false

display magic

Answer 2

您没有检查矩阵是否为方形，您没有检查矩阵中的数字是否唯一。除此之外，您还有一个严重的编码问题：你的循环都以

结尾

sant = s

他们从

开始

if(s != sant):

但你刚刚让他们平等......

无论矩阵是否为魔方，返回true或false的程序

2 个答案: