如何将抽象基类转换为通用派生类并访问子类的属性？

Question

我的类层次结构如下：

[DataContract]
[Serializable]
[KnownType(typeof(ChildClass2<>))]
public abstract class BaseClass
{
    protected BaseClass(string property1)
    {
        this.Property1 = property1;
    }

    [DataMember]
    public string Property1 { get; private set; }

    public abstract bool Method1(string inputValue);
}


[DataContract]
[Serializable]
public abstract class ChildClass1<T> : BaseClass
{
    protected ChildClass1(string property1, T property2) : base(property1) 
    {
        this.Property2 = property2;
    }

    [DataMember]
    public T Property2 { get; private set; }
}


[DataContract]
[Serializable]
public class ChildClass2<T> : ChildClass1<T>
{
    public ChildClass2(string proprty1, T property2)
        : base(property1, property2)
    {
    }

    public override bool Method1(string inputValue)
    {
      // Some processing....

    }
}

现在我将ChildClass2实例化为baseClass类型，如下所示：

BaseClass baseClass = ChildClass2<string>("test1", "test2");

如何将baseClass转换为ChildClass2类型以便我可以访问baseClass.Property2？

我试过像（ChildClass2）这样的东西.baseClass.Property2不起作用。

Answer 1

BaseClass baseClass = ChildClass2<string>("test1", "test2");
string value = ((ChildClass2<string>) baseClass).Property2;