对于我的应用,我定义了以下模型:
class Person(CrunchrModel):
MALE = "M"
FEMALE = "F"
OTHER = "O"
UNKNOWN = "U"
GENDER_CHOICES = (
(MALE, "Male"),
(FEMALE, "Female"),
(UNKNOWN, "Other"),
)
firstName = models.CharField(max_length=200, null=True, db_column="firstname")
lastName = models.CharField(max_length=200, null=True, db_column="lastname")
gender = models.CharField(max_length=1, choices=GENDER_CHOICES, default=UNKNOWN, null=True)
dateOfBirth = models.DateField(null=True, db_column="dateofbirth")
dateInService = models.DateField(null=True, db_column="dateinservice")
photo = models.ImageField(upload_to='person_photos', null=True)
class Position(Protected):
positionId = models.CharField(max_length=200, unique=True, db_column="positionid")
title = models.CharField(max_length=200, null=True)
# There cannot be a DB constraint, as that would make it impossible to add the first position.
dottedLine = models.ForeignKey("Position", to_field='positionId', related_name="Dotted Line",
null=True, db_constraint=False, db_column="dottedline_id")
solidLine = models.ForeignKey("Position", to_field='positionId', related_name="SolidLine",
null=True, db_constraint=False, db_column="solidline_id")
grade = models.ForeignKey(Grade)
businessUnit = models.ForeignKey(BusinessUnit, null=True, db_column="businessunit_id")
functionalArea = models.ForeignKey(FunctionalArea, db_column="functionalarea_id")
location = models.ForeignKey(Location, db_column="location_id")
class Employee(models.Model):
person = models.OneToOneField(Person, db_column="person_id")
fte = models.IntegerField(default=100)
dataSource = models.ForeignKey(DataSource, db_column="datasource_id")
talentStatus = models.ForeignKey(TalentStatus, db_column="talentstatus_id")
retentionRisk = models.ForeignKey(RetentionRisk, db_column="retentionrisk_id")
retentionRiskReason = models.ForeignKey(RetentionRiskReason, db_column="retentionriskreason_id")
performanceStatus = models.ForeignKey(PerformanceStatus, db_column="performancestatus_id")
potential = models.ForeignKey(Potential, db_column="potential_id")
mobility = models.ForeignKey(Mobility, db_column="mobility_id")
currency = models.ForeignKey(Currency, null=True, db_column="currency_id")
grade = models.ForeignKey(Grade, db_column="grade_id")
position = models.OneToOneField(Position, to_field='positionId', null=True,
blank=True, db_column="position_id")
employeeId = models.CharField(max_length=200, unique=True, db_column="employeeid")
dateInPosition = models.DateField(null=True, db_column="dateinposition")
class Succession(models.Model):
position = models.ForeignKey(Position, to_field='positionId', db_column="position_id")
employee = models.ForeignKey(Employee, to_field='employeeId', db_column="employee_id")
term = models.ForeignKey(SuccessionTerm)
我正在尝试建立一个继任网络。为此,我正在创建一个表格,其中包含每位员工的职位ID,姓名,职位以及他/她排队等候的职位。
我有一个工作视图,但由于一些效率低下的查询,它很慢:
employees = Employee.objects.all().prefetch_related('person', 'position')
successions = Succession.objects.all().prefetch_related('position', 'employee')
for emp in employees:
succeeds = []
for s in successions.filter(employee=emp):
succeeds.append(s.position.positionId)
# Store emp.position.positionId, emp.person.lastName, emp.position.title, succeeds
有没有办法,不使用原始SQL(由于应用程序中的其他限制),使这更有效?
答案 0 :(得分:1)
我认为您不需要原始SQL:您应该能够在Employee prefetch_related中遵循与Succession的关系。您根本不需要单独查询Succession。
employees = Employee.objects.all().prefetch_related('person', 'position', 'succession_set__position')
现在,在您的模板中,您可以迭代它:
{% for emp in employees %}
{{ emp.position.title }
{% for succ in emp.succession_set.all %}
{{ succ.position.title }}
{% endfor %}
{% endfor %}