Question

您好我需要使用Jackson-dataformat XMLMapper从JAVA创建XML。 XML应该像

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>Hong Kong</city>
      <state>Hong Kong</state>
    </addresses>
</Customer>

但我总是喜欢额外的“＆lt; addresses＆gt;＆lt; / addresses＆gt;”标签

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
<addresses>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>Hong Kong</city>
      <state>Hong Kong</state>
    </addresses>
<addresses>
</Customer>

我使用下面的代码来创建XML

JaxbAnnotationModule jaxbAnnotationModule = new JaxbAnnotationModule();
XmlMapper mapper = new XmlMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
mapper.registerModule(jaxbAnnotationModule);
mapper.registerModule(new GuavaModule());
String xml = mapper.writeValueAsString(customer);
System.out.println(xml);

请有人帮助我吗？如何删除额外的标签呢。我试过使用@XmlElement，但它没有帮助。 TIA !!

Answer 1

尝试以下代码

@JacksonXmlRootElement(localName = "customer") 
class Customer {

    @JacksonXmlProperty(localName = "id")
    private int id;
    @JacksonXmlProperty(localName = "name")
    private String  name;

    @JacksonXmlProperty(localName = "addresses")
    @JacksonXmlElementWrapper(useWrapping = false)
    private Address[] address;

    //getters, setters, toString
}

class Address {

    @JacksonXmlProperty(localName = "city")
    private String city;

    @JacksonXmlProperty(localName = "state")
    private String state;
    // getter/setter 
}

Answer 2

如果您不想在代码中的任何位置处理注释，此设置会更改默认包装行为。

XmlMapper mapper = new XmlMapper();
mapper.setDefaultUseWrapper(false);

Answer 3

只是要添加ManojP的答案，如果在变量声明中添加@JacksonXmlElementWrapper(useWrapping = false)并不起作用（对我来说就是这种情况），将其添加到getter方法将诀窍。

使用Jackson XML映射器将Java List序列化为XML

3 个答案: