Question

我有两个要比较的列表，并打印出两者中的共同点

things=['Apple', 'Orange', 'Cherry','banana','dog','door','Chair']
otherThings=['Apple', 'Orange','TV' ,'Cherry','banana','Cat','Pen','Computer','Book']
if (things == otherThings): # this condtion will not work
        print "%s\t%s" % (things, otherThings)
else:
        print "None"

问题：在这种情况下我应该使用什么条件？

预期结果： ['Apple', 'Orange','Cherry','banana']

Answer 1

一种方法是使用set和逻辑and：

>>> set(things) & set(otherThings)
set(['Orange', 'Cherry', 'Apple', 'banana'])

Answer 2

将这些转换为sets instead，然后获取两者的交集。

代码段：

things = set(['Apple', 'Orange', 'Cherry','banana','dog','door','Chair'])
otherThings = set(['Apple', 'Orange','TV' ,'Cherry','banana','Cat','Pen','Computer','Book'])
print things & otherThings

Answer 3

列表理解将为您的预期结果＆＃34;

构建列表

>>> [thing for thing in things if thing in otherThings]
['Apple', 'Orange', 'Cherry', 'banana']

改为做印刷品：

for thing in things:
    if thing in otherThings:
        print "%s\t%s" % (thing, thing)

更像是

Apple    Apple
...

比较列表和打印常见

3 个答案: