MySQL Error 1215但适用于JS Fiddle / Sqlite

Question

我正在为一个学校项目做这个，现在我们假设使用MySQL而不是我们想要的任何东西，我不知道为什么外键的WorksFor会产生1215个错误。

CREATE TABLE     Employees(
    employee_id        INT (8),
    last_name        VARCHAR (30),
    first_name        VARCHAR (30),
    status            CHAR (7),
PRIMARY KEY (employee_id)
);

CREATE TABLE    Departments(
    department_name        VARCHAR (25),
    department_master_key    CHAR (3),
PRIMARY KEY (department_name)
);

CREATE TABLE    WorksFor(
    department_name    VARCHAR (25),
    employee_id        INT (8) ,
PRIMARY KEY (department_name, employee_id),
FOREIGN KEY (employee_id) REFERENCES Employees (employee_id),
FOREIGN KEY (department_name) REFERENCES Departments (department_name)
);