Question

我一直在研究这个问题，并且终于使我的工作成功了。我意识到我的代码效率非常低，并且这显示了加载数据需要很长时间。

我正在使用SQL查询创建一个数组，如下所示......

function table_data()
{
global $wpdb;
$blogusers = get_users('blog_id=1&orderby=nicename&role=client');
$form = GFFormsModel::get_form_meta( '337' ); 
        foreach( $form['fields'] as $field ) {
        if ( $field['adminLabel'] == 'I_BD' )
            $clientid_field = $field['id'];
        }
$example_data = array();
    foreach ($blogusers as $user)
        {

        $todaysdate = date("Y-m-d");
        $count0 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$todaysdate%' AND a.field_number = '$clientid_field'" );

        $onedayago = date("Y-m-d", strtotime( '-1 days' ) );
        $count1 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$onedayago%' AND a.field_number = '$clientid_field'" );

        $twodaysago = date("Y-m-d", strtotime( '-2 days' ) );
        $count2 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$twodaysago%' AND a.field_number = '$clientid_field'" );

        $threedaysago = date("Y-m-d", strtotime( '-3 days' ) );
        $count3 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$threedaysago%' AND a.field_number = '$clientid_field'" );

        $fourdaysago = date("Y-m-d", strtotime( '-4 days' ) );
        $count4 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$fourdaysago%' AND a.field_number = '$clientid_field'" );

        $fivedaysago = date("Y-m-d", strtotime( '-5 days' ) );
        $count5 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$fivedaysago%' AND a.field_number = '$clientid_field'" );

        $sixdaysago = date("Y-m-d", strtotime( '-6 days' ) );
        $count6 = $wpdb->get_results("SELECT COUNT(*) AS count FROM l_detail a JOIN g_lead b ON b.id = a.l_id WHERE a.value = '$user->user_login' AND b.date_created LIKE '%$sixdaysago%' AND a.field_number = '$clientid_field'" );

        $arrData=array("client"=>"$user->user_login","sixdaysago"=>$count6[0]->count,"fivedaysago"=>$count5[0]->count,"fourdaysago"=>$count4[0]->count,"threedaysago"=>$count3[0]->count,"twodaysago"=>$count2[0]->count,"yesterday"=>$count1[0]->count,"today"=>$count0[0]->count,"total"=>$count[0]->count);
        array_push($example_data, $arrData);
    }   
    return $example_data;
}

正如我所提到的，这可以正常工作，但需要很长时间来处理有时服务器崩溃的数据。

如何才能提高效率？我意识到我可能以完全错误的方式写了这个，所以我希望受到教育！

Answer 1

您可以使用单个查询获取所有这些数据。只需选择少于7天的所有行，然后按用户ID和DAY（date_created）分组。然后，您可以根据输出的需要将该数据读入任何适当的多维数组。确保连接，过滤和分组中使用的所有列都有索引。

从运行速度非常慢的SQL查询创建数组

1 个答案: