Question

class BillableEvent < ActiveRecord::Base
  has_many :billable_jobs
end

class BillableJob < ActiveRecord::Base
  belongs_to :billable_event
  belongs_to :job
end

class Job < ActiveRecord::Base
  has_many :billable_jobs
  belongs_to :customer
  acts_as_list scope: :customer_id
  default_scope {order(:position)}
end

class Customer < ActiveRecord::Base
  has_many :jobs
end

class BillableEventController < ApplicationController
  def invoice
    @billable_jobs = @billable_event.billable_jobs
    @jobs = # ... what should I put here?
  end
end

在我看来，我想看看：

%table.invoice
  - @jobs.each do |job, billable_jobs|
    %tbody
      %tr.title
        %td.title{colspan: '4'}= job.stand_alone_title
      - billable_jobs.each do |billable_job|
        = content_tag_for(:tr, billable_job) do
          %td &nbsp;
          %td= billable_job.user.name
          %td= billable_job.billable_price
          %td= button_to 'Invoice'

例如：

Amber - Job 1
  A-BillableJob $10
  B-BillableJob $25
Amber - Job 2
  A-BillableJob $10
Paul
  A-BillableJob $25
  B-BillableJob $10

根据客户标题对作业进行分组和排序的位置。（上面的名称将是作业的stand_alone_title的示例，它来自客户标题。）我知道按客户对作业进行分组的每种方式都将其转换为我似乎无法排序的哈希或数组正常。

Answer 1

您可以执行group_by并将其转换为数组，但您可以使用Array类中存在的sort_by方法对数组进行排序。

class BillableEventController < ApplicationController
  def invoice
    @billable_jobs = @billable_event.billable_jobs
    # group records by customer
    customers = @billable_jobs.group_by{|e| e.job.customer}
    # when you call group_by it creates array
    # [<customer> => [<billable_j1>, <billable_j2>, ..], <customer_2> => [<billable_j>, ...]]
    @customers = jobs.sort_by{|customer, jobs| customer.title}
    # method sort_by from Array class sorts array
    # and takes argument to sort by
  end
end

如何按rails中的嵌套属性进行分组和排序？

1 个答案: