Question

我有一个数组，我想过滤它只包含符合特定条件的项目。这可以在JavaScript中完成吗？

一些例子：

[1, 2, 3, 4, 5, 6, 7, 8] // I only want [2, 4, 6, 8], i.e. the even numbers

["This", "is", "an", "array", "with", "several", "strings", "making", "up", "a", "sentence."] // I only want words with 2 or fewer letters: ["is", "an", "up", "a"]

[true, false, 4, 0, "abc", "", "0"] // Only keep truthy values: [true, 4, "abc", "0"]

Answer 1

为此，您可以使用ECMAScript5中引入的Array#filter()方法。除了IE8和更低版本以及Firefox的古老版本之外，所有浏览器都支持它。如果由于某种原因，您需要支持这些浏览器，则可以使用polyfill作为方法。

filter()将函数作为其第一个参数。对于数组的每个项，您的函数都传递三个参数 - 当前项的值，它在数组中的索引以及数组本身。如果您的函数返回true（或真值，例如1，"pizza"或42），则该项将包含在结果中。否则，它不会。 filter()返回 new 数组 - 原始数组将保持不变。这意味着您需要在某处保存值，否则它将丢失。

现在，在问题的例子中：

var myNumbersArray = [1, 2, 3, 4, 5, 6, 7, 8];
console.log(myNumbersArray.filter(function(num){
  return !(num % 2); // keep numbers divisible by 2
}));
console.log(myNumbersArray); // see - it hasn't changed!

var myStringArray = ["This", "is", "an", "array", "with", "several", "strings", "making", "up", "a", "sentence."];
console.log(myStringArray.filter(function(str){
  return str.length < 3; // keep strings with length < 3
}));
console.log(myStringArray);

var myBoolArray = [true, false, 4, 0, "abc", "", "0"];
console.log(myBoolArray.filter(Boolean));
// wow, look at that trick!
console.log(myBoolArray);

为了完整起见，还有一个使用索引和数组参数的示例：从数组中删除重复项：

var myArray = [1,1,2,3,4,5,6,1,2,8,2,5,2,52,48,123,43,52];
console.log(myArray.filter(function(value, index, array) {
   return array.indexOf(value) === index;
}));

Answer 2

要过滤不严格数组的条目，因此在原型上没有.filter属性，但仍可迭代（如document.getElementsByTagName），您可以使用

Array.prototype.filter.call(collection, function filterFunction(el, index, collection) {
    ... 
});

或简写

[].filter.call(collection, function filterFunction(el, index, collection) {
    ...
});

对于不可迭代的对象，但您仍希望过滤属性并获取通过过滤的键数组，您可以像Object.keys那样结合：

var obj = { one: 1, two: 2, three: 3, four: 4 };
var filtered = Object.keys(obj).filter(function(key) {
    return obj[key] % 2 === 0;
}); //filtered == ['two', 'four']

然后，您可以创建一个包含这些属性的新对象：

var filteredObj = filtered.reduce(function(newObj, currentKey) {
    newObj[currentKey] = obj[currentKey]; //Add the original value to the new object
    return newObj; //Return the new object to continue iteration
}, {}) // Begin iteration with a blank object

//filteredObj is now { two: 2, four: 4 }

以上甚至可以组合成一个函数！

function filterObject(obj, testCallback) {
    return Object.keys(obj).filter(function(key, index, array) {
        return testCallback(obj[key], index, array); //Call original filter but pass the property
    }).reduce(function(newObj, currentKey) {
        newObj[currentKey] = obj[currentKey]; //Add the original value to the new object
        return newObj; //Return the new object to continue iteration
    }, {}); // Begin iteration with a blank object
}

并像这样使用：

var obj = { one: 1, two: 2, three: 3, four: 4 };
var filteredObj = filterObject(obj, function(el) { return el % 2 === 0 });

Answer 3

@Scimonster使用ES6语法后的一个更简洁的答案是：

 // even numbers
const even = [1, 2, 3, 4, 5, 6, 7, 8].filter(n => n%2 == 0);
// words with 2 or fewer letters
const words = ["This", "is", "an", "array", "with", "several", "strings", "making", "up", "a", "sentence."].filter(el => el.length <= 2);
// truable elements
const trues = [true, false, 4, 0, "abc", "", "0"].filter(v => v);

console.log(even);
console.log(words);
console.log(trues);

如何只保留符合特定条件的数组项？

3 个答案: