Question

我有以下代码：

class Person

 attr_reader :name, :balance
 def initialize(name, balance=0)
    @name = name
    @balance = balance
    puts "Hi, #{name}. You have $#{balance}!"
 end
 end

class Bank

 attr_reader :bank_name
 def initialize(bank_name)
    @bank_name = bank_name
    puts "#{bank_name} bank was just created."
 end

 def open_account(name)
    puts "#{name}, thanks for opening an account at #{bank_name}!"
 end
 end

  chase = Bank.new("JP Morgan Chase")
  wells_fargo = Bank.new("Wells Fargo")
  me = Person.new("Shehzan", 500)
  friend1 = Person.new("John", 1000)
  chase.open_account(me)
  chase.open_account(friend1)
  wells_fargo.open_account(me)
  wells_fargo.open_account(friend1)

当我致电chase.open_account(me)时，我得到了结果Person:0x000001030854e0, thanks for opening an account at JP Morgan Chase!。我似乎得到了 unique_id （？）而不是我创建me = Person.new("Shehzan", 500),时分配给@name的名称。我已经阅读了很多关于类/实例变量的内容，但似乎无法弄明白。

Answer 1

这是因为您传递的是分配给name变量的实例对象。你必须这样做：

 def open_account(person)
    puts "#{person.name}, thanks for opening an account at #{bank_name}!"
 end

或者：

wells_fargo.open_account(friend1.name)

Answer 2

这里传递Person的实例，而不是字符串。

  chase.open_account(me)

您必须通过me.name或修改open_account方法才能像这样调用Person#name

def open_account(person)
  puts "#{person.name}, thanks for opening an account at #{bank_name}!"
end

Answer 3

将对象传递给open_account方法

你需要做

def open_account(person)
  puts "#{person.name}, thanks for opening an account at #{bank_name}!"
end

Ruby：使用其他类的实例变量

3 个答案: