Question

我对Python很新。我有一个词典列表。

[{"x": "23"}, {"x": "14"}, {"x": "9"}, {"x": "19"}, {"x": "21"}, {"x": "14"}, {"x": "16"}, {"x": "11"}, {"x": "9"}, {"x": "6"}, {"x": "24"}, {"x": "13"}]

我想提取与x键关联的值并绘制它们。要做到这一点，列表必须如下所示，值必须是整数（或浮点数）。

[23, 14, 9, 19, 21, 14, 16, 11, 9, 6, 24, 13]

我的问题是：我如何

提取这些值，
将它们转换为整数？

Answer 1

这可以使用字典的get方法使用列表理解来完成。

>>> l = [{"x": "23"}, {"x": "14"}, {"x": "9"}, {"x": "19"}, {"x": "21"}, {"x": "14"}, {"x": "16"}, {"x": "11"}, {"x": "9"}, {"x": "6"}, {"x": "24"}, {"x": "13"}]
>>> [i.get('x') for i in l]
['23', '14', '9', '19', '21', '14', '16', '11', '9', '6', '24', '13']

如果你喜欢它们作为整数，请在列表理解

中转换它们

>>> [int(i.get('x')) for i in l]
[23, 14, 9, 19, 21, 14, 16, 11, 9, 6, 24, 13]

Answer 2

使用list comprehension。对于每个项目，获取"x"并转换为int：

[int(item['x']) for item in mylist]

如果您需要花车，请将int更改为float。

Answer 3

您可以使用list comprehension

>>> mylist = [{'x': '23'}, {'x': '14'}, {'x': '9'}, {'x': '19'}, {'x': '21'}, {'x': '14'}, {'x': '16'}, {'x': '11'}, {'x': '9'}, {'x': '6'}, {'x': '24'}, {'x': '13'}]
>>> [ int(item.values()[0]) for item in mylist]
[23, 14, 9, 19, 21, 14, 16, 11, 9, 6, 24, 13]

或map

>>> map(lambda x: int(x['x']), mylist)
[23, 14, 9, 19, 21, 14, 16, 11, 9, 6, 24, 13]

Python dict值为整数列表

3 个答案: