Question

我需要始终从我的数据库获得最长的匹配。

MyDatabase （id /词组）
1：＆＃39;我＆＃39;
2：＆＃39;去＆＃39;
3：＆＃39;我去学校＆＃39;
4：＆＃39;＆＃39;
5：＆＃39;我的狗名叫Gogo＆＃39;
6：＆＃39; day＆＃39;
7：＆＃39;每天＆＃39;
8：＆＃39;除了＆＃39;
9：＆＃39;除了周末＆＃39;
10：＆＃39;周末＆＃39;

用户输入 =＆＃39; AwordThatsNOTinDB每天我和我的狗Gogo上学AwordThatsNOTinDB，除了周末AwordThatsNOTinDB＆＃39;

因此，当用户输入上述内容时，我希望从数据库中按顺序获取以下ID作为数组：
阵列（＆＃34;没发现的＆＃34 ;, 3，＆＃34;没发现的＆＃34 ;, 5,7,9，＆＃34;没发现的＆＃34）;

Answer 1

我会使用这个解决方案：

1-按字符串的长度从数据库顺序中选择所有字符串。

2-循环遍历我的db字符串并在用户输入中替换它们。如果字符串更改我更新了oringal字符串，并将我所在的字符串的id添加到找到的数组中。

 $found_phrase=array();
 $string=strtolower('AwordThatsNOTinDB I go to school AwordThatsNOTinDB with my dog named Gogo every day except weekends AwordThatsNOTinDB');  

 // LIMIT DB-SEARCH  
 $string=preg_replace('!\s+!', ' ', $string); // replace multiple spaces with one space
 $where=explode(" ",$string);
 foreach($where as $whereVal){
   $whereQuery=$whereQuery." phrase LIKE '%".$whereVal."%' OR";  
 }
 $whereQuery=rtrim($whereQuery,"OR"); // delete last OR
 $whereQuery="WHERE ".$whereQuery." ";    

 $query=$conn->prepare("SELECT id, phrase FROM table $whereQuery ORDER BY length(phrase) DESC");
 $query->execute();
 while($array=$query->fetch(PDO::FETCH_ASSOC)){
     $new_string=str_replace(strtolower($array['phrase']), "[{$array['id']}]", $string);
     if($new_string!=$string){
         $string=$new_string;
     }
 }
 $string=preg_replace('/([A-Z0-9,.]){1,} /i', ' Not-Found ', $string);
 $string=preg_replace('/\[([0-9])*\]/i', str_replace(array('[',']'), '',"$1"), $string);
 $string_array=explode(' ', $string);
 print_r($string_array);

Answer 2

请从数据库中获取此数组

$phrases=array(
    '1'=> 'I',
    '2'=> 'go',
    '3'=> 'I go to school',
    '4'=> 'with',
    '5'=> 'with my dog named Gogo',
    '6'=> 'day',
    '7'=> 'every day',
    '8'=> 'except',
    '9'=> 'except weekends',
    '10'=>'weekends'
);

$user_input = 'AwordThatsNOTinDB I go to school AwordThatsNOTinDB with my dog named Gogo every day except weekends AwordThatsNOTinDB';
$matches=array();

foreach($phrases as $id=>$phrase){
    $x=false;
    if(strpos($user_input,$phrase)!==false){


    if(!empty($matches)){
        foreach($matches as $key=>$match){
            if((strpos($phrase,$match)!==false) && $phrase !== $match)
                unset($matches[$key]);

            if((strpos($match,$phrase)!==false)){
                 $x = true;
                break;
            }

        }
    }
    if(!$x)
        $matches[$id]=$phrase;


}
}
var_dump($matches);
?>

mysql php查询找到最长匹配的输入部分

2 个答案: