Question

我有这个问题而且我不太清楚如何回答它 - 我能够阅读文件但不确定如何只显示超过10个字符的单词

Answer 1

这应该有效：

private static void readFile(File fin) throws IOException {
    FileInputStream fis = new FileInputStream(fin);

    BufferedReader br = new BufferedReader(new InputStreamReader(fis));

    String line = null;
    while ((line = br.readLine()) != null) {
        if(line.length()>10) System.out.println(line);
    }

    br.close();
}

Answer 2

在String变量中使用名为word：

的变量

 if (word.length() > 10)
      System.out.println(word);

PS：google之前询问!!

Answer 3

这里有一些伪代码可以帮助你入门

create empty list //where we'll add all the >10char words
read file(split per newline) //see the apache commons api
for each line
    split on space
    for each word in splitted sentence
        if wordLength > 10 add to empty list
print each entry in your filled list

Answer 4

虽然其他答案是正确的，但我建议使用scanner类来读取文件，因为它可以安全地检测文件结束条件并具有更简单/更有用的实用方法： -

Scanner input = new Scanner(new File("file.txt"));
while(input.hasNextLine())
{
   String word = input.nextLine();
   if(word.length()>10){
      System.out.println(word)
     }
}

Answer 5

这是你的逻辑。

import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStreamReader;



    public class Test {

        public static void main(String[] args) throws Exception{

            FileInputStream fis = new FileInputStream(new File("your.txt"));    // path for the text file

            BufferedReader br = new BufferedReader(new InputStreamReader(fis));

            String line = null;

            while ((line = br.readLine()) != null) {
                String st[] = line.split(" ");
                for(int i=0; i<st.length; i++){
                    if(st[i].length()>10) System.out.println(st[i]);
                }

        }
        }

    }

如何打印文件中只有10个以上字符的单词？

5 个答案: