Question

我需要从alertcontroller中的文本字段中获取文本作为NSString，但是当我尝试返回某些内容时，我会收到错误＆＃34;不兼容的块指针类型发送NSString＆＃34;

我可以获取值并使其在处理程序中的NSLog中显示，但不在其外部。

    UIAlertAction *enterAction = [UIAlertAction
                              actionWithTitle:@"Enter"
                              style:UIAlertActionStyleDefault
                              handler:^(UIAlertAction *action) {
                                  NSLog(@"Enter Action");
                                  NSString *name = ((UITextField *)[alertController.textFields objectAtIndex:0]).text;
                                  NSString *time = ((UITextField *)[alertController.textFields objectAtIndex:1]).text;
                                  [alertController dismissViewControllerAnimated:YES completion:nil];
                                  NSLog(@"%@", name);
                                  NSLog(@"%@", time);
                                  return name;
                              }];

完整的代码就在这里

- (void)textPopUp{

    UIAlertController * alertController = [UIAlertController
                                       alertControllerWithTitle:@"Attention!"
                                       message:@"Please enter project name, and time spent below"
                                       preferredStyle:UIAlertControllerStyleAlert];

    UIAlertAction *cancelAction = [UIAlertAction
                               actionWithTitle:@"Cancel"
                               style:UIAlertActionStyleCancel
                               handler:^(UIAlertAction *action){
                                   [alertController dismissViewControllerAnimated:YES completion:nil];
                                   NSLog(@"Cancel Action");
                               }];

    UIAlertAction *enterAction = [UIAlertAction
                              actionWithTitle:@"Enter"
                              style:UIAlertActionStyleDefault
                              handler:^(UIAlertAction *action) {
                                  NSLog(@"Enter Action");
                                  NSString *name = ((UITextField *)[alertController.textFields objectAtIndex:0]).text;
                                  NSString *time = ((UITextField *)[alertController.textFields objectAtIndex:1]).text;
                                  [alertController dismissViewControllerAnimated:YES completion:nil];
                                  NSLog(@"%@", name);
                                  NSLog(@"%@", time);
                                  return name;
                              }];

    [alertController addTextFieldWithConfigurationHandler:^(UITextField *textField) {
    textField.placeholder = NSLocalizedString(@"Name", @"Name");
    }];

    [alertController addTextFieldWithConfigurationHandler:^(UITextField *textField) {
    textField.placeholder = NSLocalizedString(@"Time", @"Time");
    }];

    [alertController addAction:cancelAction];
    [alertController addAction:enterAction];
    [self presentViewController:alertController animated:YES completion:nil];
}

Answer 1

此错误显示，因为在UIAlertAction处理程序中返回字符串。您可以将textField文本设置为控制器：

__weak TableViewController *weakSelf = self;

UIAlertAction *enterAction = [UIAlertAction
                              actionWithTitle:@"Enter"
                              style:UIAlertActionStyleDefault
                              handler:^(UIAlertAction *action) {
                                  NSString *name = ((UITextField *)[alertController.textFields objectAtIndex:0]).text;
                                  NSString *time = ((UITextField *)[alertController.textFields objectAtIndex:1]).text;
                                  [alertController dismissViewControllerAnimated:YES completion:nil];
                                  weakSelf.result = name;
                              }];

从AlertController文本字段获取字符串时出错

1 个答案: