Question

输出为

如果我输入1，我希望新输出为

我尝试过使用布尔语句和while（true），但我无法弄明白。这是一些示例代码

String table[][];
table = new String[3][3];
int options[][]={{1,2,3},{4,5,6},{7,8,9}};

while(true){
    for (int i = 0; i < table.length; i++) {
        for (int j = 0; j < table[i].length; j++) {
            table[i][j] = "—";

            System.out.print(table[i][j] + " ");
    } //FOR LOOP 2
        System.out.println();
    }// FOR LOOP 1
    for (int i = 0; i < options.length; i++) {
        for (int j = 0; j < options[i].length; j++) {

            System.out.print(options[i][j]+ " ");
        }// FOR LOOP 2(2)
        System.out.println();
    }// FOR LOOP 1(1)
        // ASK FOR MOVE ONE

    System.out.println("Player One (x) : Enter a move from 1-9 >>> ");
    int x = in.nextInt();

    if (x==1){
        table[0][0]="x";
        return true; //DOES NOT WORK. I WANT IT TO RETURN TO TOP WITH THE VALUE table[0][0] = x
    }

当我输入1时，我的输出仍然是 - - - - - - - - - 1 2 3 4 5 6 7 8 9

Answer 1

使用布尔变量标志来检查条件

boolean flag=false;

if if loop assign flag true

if (x==1){
        table[0][0]="x";
        flag=true;
}

使用do ... while循环而不是while循环

 do{

    }while(flag)

以下是更新的代码：

boolean flag=false;

do{
    for (int i = 0; i < table.length; i++) {
        for (int j = 0; j < table[i].length; j++) {
            table[i][j] = "—";

            System.out.print(table[i][j] + " ");
    } //FOR LOOP 2
        System.out.println();
    }// FOR LOOP 1
    for (int i = 0; i < options.length; i++) {
        for (int j = 0; j < options[i].length; j++) {

            System.out.print(options[i][j]+ " ");
        }// FOR LOOP 2(2)
        System.out.println();
    }// FOR LOOP 1(1)
        // ASK FOR MOVE ONE

    System.out.println("Player One (x) : Enter a move from 1-9 >>> ");
    int x = in.nextInt();

    if (x==1){
        table[0][0]="x";
        flag=true;
    }
}while(flag);

Answer 2

您应该将数组的初始化删除到while循环之外：

// init the array
for (int i = 0; i < table.length; i++) {
    for (int j = 0; j < table[i].length; j++) {
        table[i][j] = "—";
    } 
}
while(true){
    // print the array
    for (int i = 0; i < table.length; i++) {
        for (int j = 0; j < table[i].length; j++) {
            System.out.print(table[i][j] + " ");
        } 
        System.out.println();
    }
    for (int i = 0; i < options.length; i++) {
        for (int j = 0; j < options[i].length; j++) {
            System.out.print(options[i][j]+ " ");
        }// FOR LOOP 2(2)
        System.out.println();
    }// FOR LOOP 1(1)
    // ASK FOR MOVE ONE
    System.out.println("Player One (x) : Enter a move from 1-9 >>> ");
    int x = in.nextInt();
    if (x==1){
        table[0][0]="x";
    }
}

这样，您就不会在循环的每次迭代中重置数组。

另外，不要在你的条件中放置一个return语句，因为那会破坏循环并且不会打印更新的数组。

Answer 3

但是，为了修复您的代码，以下操作将会如此。请仔细阅读您的解决方案以简化

int userInput = -1;

while(true){
    for (int i = 0; i < table.length; i++) {
        for (int j = 0; j < table[i].length; j++) {
           if (userInput ==1){
              table[0][0]="x";
           }else {
             table[i][j] = "—";
            }

            System.out.print(table[i][j] + " ");
        } //FOR LOOP 2
        System.out.println();
    }// FOR LOOP 1
    for (int i = 0; i < options.length; i++) {
        for (int j = 0; j < options[i].length; j++) {

            System.out.print(options[i][j]+ " ");
        }// FOR LOOP 2(2)
        System.out.println();
    }// FOR LOOP 1(1)
        // ASK FOR MOVE ONE

    System.out.println("Player One (x) : Enter a move from 1-9 >>> ");
    userInput = in.nextInt();

如何更改二维数组中的值

3 个答案: