Question

我知道如何处理方法jsonObj.toString（）但我有理由不能这样做。我的JSONObject里面有一个JSONArray，它有太多的数据，所以如果我将它转换为String然后转换回我害怕它达到String类型的限制。所以我想传递一个纯对象，而不是使用该方法。我实现了Parcelable接口来做到这一点，但是我得到了错误＆＃34; java.lang.RuntimeException：Parcel：无法编组值＆＃34;

public class MJSONObject implements Parcelable {
private JSONObject jsonObject;

public MJSONObject() {
}

public MJSONObject(JSONObject jsonObject) {
    this.jsonObject = jsonObject;
}

public void set(JSONObject jsonObject) {
    this.jsonObject = jsonObject;
}

public JSONObject get() {
    return jsonObject;
}

@Override
public int describeContents() {
    // TODO Auto-generated method stub
    return 0;
}

public static final Parcelable.Creator<MJSONObject> CREATOR = new Parcelable.Creator<MJSONObject>() {
    public MJSONObject createFromParcel(Parcel in) {
        return new MJSONObject(in);
    }

    public MJSONObject[] newArray(int size) {
        return new MJSONObject[size];
    }
};

@Override
public void writeToParcel(Parcel dest, int flags) {
    dest.writeValue(jsonObject);
}

private MJSONObject(Parcel in) {
    jsonObject = (JSONObject) in.readValue(JSONObject.class.getClassLoader());
}

Answer 1

您可以轻松地通过JSONObject转换String，就像我们使用网址发送JSONObject的某些情况一样，将其添加为String。因此，请尝试将其作为String发送，如：

intent.putExtra("jsonObject", jsonObject.toString());

并在另一方接收

Intent intent = getIntent();

String jsonString = intent.getStringExtra("jsonObject");

现在，JSON名为String的{{1}}假设它是一个响应，就像您从Web服务收到的那样，然后得到您的jsonString：

JSONObject

希望你能理解我的观点：）

Answer 2

试试这个，您还可以使用ComplexPrefereces类

将对象从一个活动转移到另一个活动

在项目中添加ComplexPreferences.java类

import android.content.Context;
import android.content.SharedPreferences;
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;
import java.lang.reflect.Type;


/**
* This class helps to store class object in the shared preferences
*
*/

public class ComplexPreferences {

private static ComplexPreferences complexPreferences;
private Context context;
private SharedPreferences preferences;
private SharedPreferences.Editor editor;
private static Gson GSON = new Gson();
Type typeOfObject = new TypeToken<Object>() {
}.getType();

private ComplexPreferences(Context context, String namePreferences, int mode) {
    this.context = context;
    if (namePreferences == null || namePreferences.equals("")) {
        namePreferences = "complex_preferences";
    }
    preferences = context.getSharedPreferences(namePreferences, mode);
    editor = preferences.edit();
}

public static ComplexPreferences getComplexPreferences(Context context,
                                                       String namePreferences, int mode) {

    if (complexPreferences == null) {
        complexPreferences = new ComplexPreferences(context,
                namePreferences, mode);
    }

    return complexPreferences;
}

public void putObject(String key, Object object) {
    if(object == null){
        throw new IllegalArgumentException("object is null");
    }

    if(key.equals("") || key == null){
        throw new IllegalArgumentException("key is empty or null");
    }

    editor.putString(key, GSON.toJson(object));
}

public void commit() {
    editor.commit();
}

public <T> T getObject(String key, Class<T> a) {

    String gson = preferences.getString(key, null);
    if (gson == null) {
        return null;
    } else {
        try{
            return GSON.fromJson(gson, a);
        } catch (Exception e) {
            throw new IllegalArgumentException("Object storaged with key " + key + " is instanceof other class");
        }
    }
}

}

将对象存储在共享首选项中，如下所示：

    ComplexPreferences complexPreferences = ComplexPreferences.getComplexPreferences(getActivity(), "store_object", 0);
    complexPreferences.putObject("class_name", className);
    complexPreferences.commit();

用于检索这样的后退对象：

    ComplexPreferences complexPreferences = ComplexPreferences.getComplexPreferences(DrawerActivity.this, "store_object", 0);
    ClassName className=complexPreferences.getObject("class_name", ClassName.class);

Answer 3

将对象作为意图传递，可串联是最好的方法。以下是从一个活动传递意图的代码

MJSONObject  mObject;
Intent intent = new Intent(FromActivity.this, ToActivity.class);
Bundle userObject = new Bundle();
userObject.putSerializable("Object", mObject);
userObject.putString("method_name", "ObjectIntent");
intent.putExtras(userObject);
startActivity(intent);

在另一项活动中，使用如下方式获取意图：

String method_name = null;
MJSONObject  mObject;
method_name = getIntent().getStringExtra("method_name");
if(method_name.equals("ObjectIntent"))
{
mObject= (MJSONObject) getObject.getSerializable("Object");
}

最后你的自定义对象的pojo类应该是：

public class MJSONObject implements Serializable {

private static final long serialVersionUID = 1L;

private JSONObject jsonObject;

public MJSONObject() {
}

public MJSONObject(JSONObject jsonObject) {
    this.jsonObject = jsonObject;
}

public void set(JSONObject jsonObject) {
    this.jsonObject = jsonObject;
}

public JSONObject get() {
    return jsonObject;
}

@Override
public int describeContents() {
    // TODO Auto-generated method stub
    return 0;
}

通过Intent将JSONObject传递给另一个活动

3 个答案: