我输入用户名和密码时会收到此错误。
致命错误:在第32行的Z:\ xampp \ htdocs \ zed \ checklogin.php中调用未定义的函数session_register()
这是代码。
main_login.php
<!DOCTYPE html>
</html lang="en">
<head>
<meta charset="utf-8">
<title>Test</title>
</head>
</body>
<table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form name="form1" method="post" action="checklogin.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td colspan="3"><strong>Member Login </strong></td>
</tr>
<tr>
<td width="78">Username</td>
<td width="6">:</td>
<td width="294"><input name="myusername" type="text" id="myusername"></td>
</tr>
<tr>
<td>Password</td>
<td>:</td>
<td><input name="mypassword" type="text" id="mypassword"></td>
</tr>
<tr>
<td> </td>
<td> </td>
<td><input type="submit" name="Submit" value="Login"></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
</body>
</html>
checklogin
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="password"; // Mysql password
$db_name="test"; // Database name
$tbl_name="members"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// username and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];
// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
header("location:login_success.php");
}
else {
echo "Wrong Username or Password";
}
?>
login_success.php
// Check if session is not registered, redirect back to main page.
// Put this code in first line of web page.
<?php
session_start();
if(!session_is_registered(myusername)){
header("location:main_login.php");
}
?>
<html>
<body>
Login Successful
</body>
</html>
logout.php
// Put this code in first line of web page.
<?php
session_start();
session_destroy();
?>
答案 0 :(得分:4)
您正在关注一个非常古老的( 和错误的 )教程。不推荐使用所有mysql_*
函数,您应该查看PDO
1 或MySQLi
2
您的错误消息:
Fatal error: Call to undefined function session_register() in Z:\xampp\htdocs\zed\checklogin.php on line 32
因为session_register()
也被弃用的国家/地区。您需要设置如下值:
$_SESSION['username'] = 'theusername';
然后在您检查用户是否已登录的页面上,您应该使用以下内容:
session_start();
if(!isset($_SESSION['username']) || empty($_SESSION['username'])) {
die(header("Location: /login"));
}
1 - PDO
2 - MySQLi
对于额外的Cookie分数,这是一个示例PDO
查询。
$db = new PDO('mysql:host=localhost;dbname=testdb;charset=utf8', 'username', 'password');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$stmt = $db->prepare("SELECT * FROM $tbl_name WHERE username=? and password=?");
$stmt->bindValue(1, $username, PDO::PARAM_STR);
$stmt->bindValue(2, $password, PDO::PARAM_STR);
if($stmt->execute()){
if($stmt->rowCount() == 1) {
$data = $stmt->fetchObject();
$_SESSION['username']
}
}
免责声明 :以上是伪代码,我建议您查看PDO PHP示例。