Question

运行SQL Server 2008，我绝对是一个新的SQL用户。

我有一个包含4列的表：

EmpNum, User, Action, Updatetime

用户登录并退出系统，它已在数据库中注册。例如，如果user1登录到系统，然后在5分钟后退出，则一个简单的查询（select * from update）将如下所示：

EmpNum   User    Action   Updatetime
1        User1   I        2010-01-01 23:00:00:000
1        User1   O        2010-01-01 23:05:00:000

我正在尝试查询Empnum，用户，操作，我（及时），O（出时间）和总时间。

Answer 1

您可以尝试类似

的内容

DECLARE @Table TABLE(
        EmpNum Int,
        [User] VARCHAR(10),
        Action VARCHAR(1),
        Updatetime DATETIME
)

INSERT INTO @Table SELECT 1,'User1','I','2010-01-01 23:00:00:000' 
INSERT INTO @Table SELECT 1,'User1','O','2010-01-01 23:05:00:000'
INSERT INTO @Table SELECT 1,'User1','I','2010-01-01 23:10:00:000' 
INSERT INTO @Table SELECT 1,'User1','O','2010-01-01 23:25:00:000'

SELECT  *,
        DATEDIFF(mi, InTime, OutTime) Period
FROM    (
            SELECT  EmpNum,
                    [User],
                    UpdateTime InTime,
                    (   SELECT  TOP 1 
                                Updatetime 
                        FROM    @Table 
                        WHERE   EmpNum = t.EmpNum 
                        AND     Action = 'O' 
                        AND     Updatetime > t.Updatetime 
                        ORDER BY Updatetime
                    ) OutTime
            FROM    @Table t
            WHERE   Action = 'I'
        ) sub

输出

EmpNum      User       InTime                  OutTime                 Period
----------- ---------- ----------------------- ----------------------- -----------
1           User1      2010-01-01 23:00:00.000 2010-01-01 23:05:00.000 5
1           User1      2010-01-01 23:10:00.000 2010-01-01 23:25:00.000 15

Answer 2

Select T1.EmpNum, T1.User, T1.UpdateTime As TimeIn
 , (Select Min(T2.UpdateTime)
      From Table As T2
      Where T2.EmpNum = T1.EmpNum
      And T2.User = T1.User
      And T2.Action = 'O'
 And T2.UpdateTime > T1.UpdateTime) As TimeOut
From Table As T1
Where Action = 'I'

编辑在评论中，您要求使用TimeWorked。由于您使用的是SQL Server 2008，因此可以使用外部应用来计算每个及时行的输出时间。然后使用DateDiff是一件简单的事。

Select T1.EmpNum, T1.User
    , T1.UpdateTime As TimeIn
    , TimeOut.UpdateTime As TimeOut
    , DateDiff(mi, T1.UpdateTime, TimeOut.UpdateTime) As TimeWorkedInMinutes
From Table As T1
    Outer Apply (
                Select Min(T2.UpdateTime) As UpdateTime
                From Table As T2
                Where T2.EmpNum = T1.EmpNum
                    And T2.User = T1.User
                    And T2.Action = 'O'
                    And T2.UpdateTime > T1.UpdateTime
                ) As TimeOut
Where Action = 'I'

SQL Server查询问题

2 个答案: