Question

我有点担心如何让python让它选择一个随机单词。用户将有5次机会显示正确的单词。

我将此视为错误

AttributeError：'builtin_function_or_method'对象没有属性'choice'

    from random import * 


word = ['hello','bye','who','what','when','mouse','juice','phone','touch','pen','book','bag','table','pencil','day','paint','screen','floor','house','roof' ]

print("You will have 5 chances to guess the correct word! ")
rounds = 5

word = random.choice(WORDS)

correct = word
length = len(word)
length = str(length)

while tries < 5:
    guess = raw_input("The word is " + length + " letters long. Guess a letter!: ")
    if guess not in word: 
        print ("Sorry, try again.")
    else:
        print ("Good job! Guess another!")

    tries += 1

final = raw_input ("Try to guess the word!: ")

if final == correct:
    print ("Amazing! My word was ", word, "!")

else:
    print("the value to guess was ",word,"\n")

Answer 1

当然，这取决于单词在该文件中的存储方式，但假设单词是用空格分隔的，那很简单：

with open("wordguessing.txt") as infile:
    wordlist = infile.read().split()
toguess = choice(wordlist)  # random.choice() chooses an item from a given iterable

Answer 2

尝试使用random.choice而不是random.randint。第二个函数将返回一个介于0和列表之间的数字，而不是单词。

我重写你的代码只是为了显示random.choice。还有很多事情需要改进：）

import random 
myList =['hello','bye','who','what','when','mouse','juice','phone','touch','pen','book','bag','table','pencil','day','paint','screen','floor','house','roof' ]

print("You will have 5 chances to guess the correct word! ")
rounds = 5
word = random.choice(myList)
toguess = (input("Enter word here: "))
if word == toguess:
    print("Amazing! You guessed it!")
else:
    print("Try again!")
print("the value to guess was ",word,"\n")

如何让Python选择一个随机单词

2 个答案: