Question

我正在关注Wrox的“开始PHP，Apache，MySQL Web开发”一书。我一直在逐字逐句，因为某些原因我遇到了代码问题。编辑说我的代码中没有错误。但是当我运行它时，给我以下消息： “您的SQL语法有错误;请查看与您的MySQL服务器版本对应的手册，以便在第3行附近使用正确的语法”，这里是以下代码

<?php
//take in the id of a director and return his/her full name
function get_director() {

global $db;

$query = 'SELECT people_fullname
          FROM people
          WHERE  people_id = ' . $director_id;
$result = mysql_query($query, $db) or die(mysql_error($db));

$row = mysql_fetch_assoc($result);
extract($row);

return $people_fullname;
}

//take in the id of a lead actor and return his/her full name
function get_leadactor($leadactor_id) {

global $db;

$query = 'SELECT people_fullname
          FROM people
          WHERE people_id = ' . $leadactor_id;
$result = mysql_query($query, $db) or die (mysql_error($db));
$extract($row);

return $people_fullname;
}

// take in the id of a movie type 
// and return the meaningful textual description
function get_movietype($type_id) {

global $db;

$query = 'SELECT movietype_label
          FROM movietype
          WHERE movietype_id = ' . $type_id;
          $result = mysql_query($query, $db) or die (mysql_error($db));

          $row = mysql_fetch_assoc($result);
          extract($row);

          return $movietype_label;
 }
   // conect to MySQL
   $db = mysql_connect('localhost', 'root', 'root') or 
   die ('unable to connect. Check your parameters');

    // make sure you are yousing the right database
    mysql_select_db('moviesite', $db) or die(mysql_error($db) );

    // retrieve information
    $query = 'SELECT movie_name, movie_year, movie_director, movie_leadactor, movie_type
           FROM movie
           ORDER BY movie_name ASC, movie_year DESC';
    $result = mysql_query($query, $db) or die ($mysql_error($db) );

    // determine number of rows in returned result
    $num_movies = mysql_num_rows($result);


    $table = <<<ENDHTML
    <div style ="text-align: center;">
    <h2>Movie Review Database</h2>
      <table border="1" cellpadding="2" cellspacing="2" style="width: 70%; margin-left: auto;     margin-right:auto;">
     <tr>
       <th>Movie Title</th>
       <th>Year of the release</th>
       <th>Movie Director</th>
       <th>Movie Lead Actor</th>
       <th>Movie Type</th>
     </tr>
     ENDHTML;

      //loop throught the results
      while ($row = mysql_fetch_assoc($result) ) {
      extract($row);
      $director = get_director($movie_director);
      $leadactor = get_leadactor($movie_leadactor);
      $movietype = get_movietype($movie_type);

      $table .= <<<ENDHTML
      <tr>
         <td>$movie_name</td>
         <td>$movie_year</td>
         <td>$director</td>
         <td>$leadactor</td>
         <td>$movietype</td>
     </tr>
     ENDHTML;

  }

  $table .= <<<ENDHTML
  </table>
  <p>$num_movies Movies</p>
  </div>
  ENDHTML;

  echo $table
  ?>

之后我尝试复制并粘贴确切的代码，可能是我做错了这里是以下代码：

 <?php
 // take in the id of a director and return his/her full name
 function get_director($director_id) {
 global $db;
 $query = 'SELECT
 people_fullname
 FROM people
 WHERE
 people_id = ' . $director_id;
 $result = mysql_query($query, $db) or die(mysql_error($db));
 $row = mysql_fetch_assoc($result);
 extract($row);
 return $people_fullname;
 }
 // take in the id of a lead actor and return his/her full name
 function get_leadactor($leadactor_id) {
 global $db;
 $query = 'SELECT
 FROM
 people WHERE
 people_id = ' . $leadactor_id;
 $result = mysql_query($query, $db) or die(mysql_error($db));
 $row = mysql_fetch_assoc($result);
 extract($row);
 return $people_fullname;
 }
 // take in the id of a movie type and return the meaningful textual
 // description
 function get_movietype($type_id) {
 global $db;
 $query = 'SELECT
 movietype_label
 FROM
 movietype
 WHERE
 movietype_id = ' . $type_id;
 $result = mysql_query($query, $db) or die(mysql_error($db));
 $row = mysql_fetch_assoc($result);
 extract($row);
 return $movietype_label;
 }

 //connect to MySQL
 $db = mysql_connect('localhost', 'root', 'root') or
 die ('Unable to connect. Check your connection parameters.');
 // make sure you’re using the right database
 mysql_select_db('moviesite', $db) or die(mysql_error($db));
 // retrieve information
 $query = 'SELECT
 movie_name, movie_year, movie_director, movie_leadactor,
 movie_type
 FROM
 movie
 ORDER BY
 movie_name ASC,
 movie_year DESC';
 $result = mysql_query($query, $db) or die(mysql_error($db));
 // determine number of rows in returned result
 $num_movies = mysql_num_rows($result);

 $table = <<<ENDHTML

 <div style="text-align: center;">
 <h2>Movie Review Database</h2>
 <table border="1" cellpadding="2" cellspacing="2"
 style="width: 70%; margin-left: auto; margin-right: auto;">
 <tr>
  <th>Movie Title</th>
  <th>Year of Release</th>
  <th>Movie Director</th>
  <th>Movie Lead Actor</th>
  <th>Movie Type</th>
 </tr>

 ENDHTML;
  // loop through the results
  while ($row = mysql_fetch_assoc($result)) {
  extract($row);
  $director = get_director($movie_director);
  $leadactor = get_leadactor($movie_leadactor);
  $movietype = get_movietype($movie_type);
  $table .= <<<ENDHTML
  <tr>
   <td>$movie_name</td>
   <td>$movie_year</td>
   <td>$director</td>
   <td>$leadactor</td>
   <td>$movietype</td>
  </tr>
   ENDHTML;
 }
 $table .= <<<ENDHTML
 </table>
 <p>$num_movies Movies</p>
 </div>
 ENDHTML;

 echo $table;
 ?>

这次我运行代码时，表头显示但部分代码也显示在浏览器上。它看起来像这样： ENDHTML; //循环结果while（= mysql_fetch_assoc（Resource id＃3））{extract（）; = get_director（）; = get_leadactor（）; = get_movietype（）; 。=＆lt;＆lt; ENDHTML; }。=＆lt;＆lt;

任何帮助将不胜感激我是编程感谢的新手

Answer 1

当你结束heredoc时，你不能在行的开头放任何字符。在你的代码中，有一些带有空格或标签的heredocs。删除空格并将你的heredoc放在行的开头。

More info on heredoc.

Answer 2

关闭heredoc语句必须位于字符串中的第一个位置：

ENDHTML;    // works
  ENDHTML;  // won’t work

问题与heredoc和PHP

2 个答案: