Question

我需要从mapquestapi获取第一个和最后一个纬度和经度，并通过街道地址。首先，传递lat和long我可以使用json.net获取house_number：

string latitu = "-33.4479021";
string longitu = "-70.6447504";
WebClient client = new WebClient();
Stream stream = client.OpenRead("http://open.mapquestapi.com/nominatim/v1/reverse.php?format=json&lat=" + latitu + "&lon=" + longitu + "");
StreamReader reader = new StreamReader(stream);

Newtonsoft.Json.Linq.JObject jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());

string houseNumber = (string)jObject["address"]["house_number"];

Console.WriteLine(houseNumber);
stream.Close();

下面的代码工作正常，但现在我需要从“svg”获取第一个和最后一个lat和long：

array ( 
0 => array 
    ( 'place_id' => '92911594', 
    'licence' => 
    'Data Â© OpenStreetMap contributors, ODbL 1.0. http://www.openstreetmap.org/copyright', 
    'osm_type' => 'way', 
    'osm_id' => '121748552', 
    'boundingbox' => array 
        ( 
            0 => '-33.4480414', 
            1 => '-33.4439319', 
            2 => '-70.6448054', 
            3 => '-70.6266944', 
        ), 
    'lat' => '-33.4460658', 
    'lon' => '-70.6359402', 
    'display_name' => 'MarÃn, Santiago, Provincia de Santiago, XIII RegiÃ³n Metropolitana de Santiago, 8331059, Chile', 
    'class' => 'highway', 
    'type' => 'tertiary', 
    'importance' => 0.2, 
    'address' => array 
    ( 
        'road' => 
        'MarÃn', 
        'city' => 
        'Santiago', 
        'county' => 
        'Provincia de Santiago', 
        'state' => 'XIII RegiÃ³n Metropolitana de Santiago', 
        'postcode' => '8331059', 
        'country' => 'Chile', 
        'country_code' => 'cl', 
    ), 
    **'svg'** => 'M **-70.626694400000005 33.444016900000001** L -70.626853100000005 33.443931900000003 -70.628024600000003 33.444266200000001 -70.629083399999999 33.444542800000001 -70.629957200000007 33.444764300000003 -70.630791099999996 33.444983999999998 -70.630836099999996 33.4449915 -70.631027500000002 33.445031299999997 -70.631102900000002 33.445044099999997 -70.631955300000001 33.445186900000003 -70.632777300000001 33.445343999999999 -70.632846900000004 33.445356799999999 -70.6329025 33.445371799999997 -70.633783199999996 33.445576199999998 -70.634021200000007 33.445624299999999 -70.635066499999994 33.4458354 -70.635940199999993 33.4460658 -70.637316900000002 33.446388900000002 -70.638039300000003 33.446610700000001 -70.638551500000005 33.446730799999997 -70.639778699999994 33.447019400000002 -70.640489099999996 33.4471962 -70.641005800000002 33.4473074 -70.642197100000004 33.447521299999998 -70.642251900000005 33.447535500000001 -70.643692900000005 33.4478121 **-70.644805399999996 33.448041400000001**', 
    ), )

我正在尝试这个，但错误说它不是一个对象：

string direcc = "marin,+santiago";
          //string url = "http://open.mapquestapi.com/nominatim/v1/search?&q="+direcc+"&format=json&addressdetails=1&limit=1&polygon_svg=1&countrycodes=cl";
          WebClient client = new WebClient();
          Stream stream = client.OpenRead("http://open.mapquestapi.com/nominatim/v1/search?&q=" + direcc + "&format=json&addressdetails=1&limit=1&polygon_svg=1&countrycodes=cl");
          StreamReader reader = new StreamReader(stream);

          Newtonsoft.Json.Linq.JObject jObject = Newtonsoft.Json.Linq.JObject.Parse(reader.ReadLine());

          string la = (string)jObject["address"]["svg"];

          Console.WriteLine(la);
          stream.Close();

这项工作，但我不知道如何获得第一个和最后一个lat和long：

string latitud = "-33.4479021";
string longitud = "-70.6447504";
string url = "http://open.mapquestapi.com/nominatim/v1/reverse.php?format=json&lat=" + latitud +"&lon=" + longitud + "";
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
          HttpWebResponse response = (HttpWebResponse)request.GetResponse();
          Stream stream = response.GetResponseStream();
          StreamReader reader = new StreamReader(stream);
          string xmlText = reader.ReadToEnd();
          Console.WriteLine(xmlText);

我能做些什么才能得到这个部分？非常感谢你！

如何从json.net获取每个jObject？

0 个答案: