我正在努力制作一个与扑克(德州扑克)合作的程序;每只手的值从1到169,我希望能够输入每张卡以及它们是否适合,并且这些值对应于一系列结构。这是到目前为止的代码,我似乎无法让它工作(我是一个初级程序员)。哦,我顺便使用visual studio 2005
#include "stdafx.h"
#include <iostream>
int main()
{
using namespace std;
struct FirstCard
{
struct SecondCard
{
int s; //suited
int n; //non-suited
};
SecondCard s14;
SecondCard s13;
SecondCard s12;
SecondCard s11;
SecondCard s10;
SecondCard s9;
SecondCard s8;
SecondCard s7;
SecondCard s6;
SecondCard s5;
SecondCard s4;
SecondCard s3;
SecondCard s2;
};
FirstCard s14; //ace
FirstCard s13; //king
FirstCard s12; //queen
FirstCard s11; //jack
FirstCard s10;
FirstCard s9;
FirstCard s8;
FirstCard s7;
FirstCard s6;
FirstCard s5;
FirstCard s4;
FirstCard s3;
FirstCard s2;
s14.s14.n = 169; // these are the values that each combination
s13.s13.n = 168; // will evaluate to, would eventually have
s12.s12.n = 167; // hand combinations all the way down to 1
s11.s11.n = 166;
s14.s13.s = 165;
s14.s13.s = 164;
s10.s10.n = 163; //10, 10, nonsuited
s14.s13.n = 162;
s14.s11.s = 161;
s13.s12.s = 160;// king, queen, suited
s9.s9.n = 159;
s14.s10.s = 158;
s14.s12.n = 157;
s13.s11.s = 156;
s8.s8.n = 155;
s12.s11.s = 154;
s13.s10.s = 153;
s14.s9.s = 152;
s14.s11.n = 151;
cout << "enter first card: " << endl;
cin >> somthing?//no idea what to put here, but this would somehow
//read out the user input (a number from 2 to 14)
//and assign it to the corresponding struct
cout << firstcard.secondcard.suited_or_not << endl; //this would change depending
//on what the user inputs
system("Pause");
}
答案 0 :(得分:2)
首先,不要通过反复试验来学习所有内容,而应考虑阅读一本好的入门书(list here)。每本值得阅读的书都解决了C ++中的基本输入以及如何处理重复代码。使用容器。
话虽如此:我对扑克一无所知,但你肯定需要阅读有关容器的内容 - 如果你反复定义变量,必须有一些方法来抽象它。
从你所拥有的开始,我们可以说我们将这些值分组在一个结构中:
struct Values {
unsigned suited;
unsigned unsuited;
Values() : suited(0), unsuited(0) {} // some default
};
然后我们可以使用允许我们通过编号访问它们的容器:
typedef std::map<unsigned, Values> SecondCardMap;
typedef std::map<unsigned, SecondCardMap> CardMap;
我们可以通过它们的数字方便地插入和修改结构:
CardMap cards;
cards[14][14].unsuited = 169;
cards[13][13].unsuited = 168;
现在你只需要阅读用户的索引:
unsigned first, second;
std::cout << "enter first: ";
std::cin >> first;
std::cout << "enter second: ";
std::cin >> second;
并且可以根据以下内容访问值:
cards[first][second].unsuited = 1234;
请注意,上述内容并未解决任何错误处理等问题。