Question

尝试根据通配符子域过滤路由。所以基本上我们有一个网站example.com。我想根据某些子域名对其进行过滤，例如local.admin.example.com和admin.example.com。

我的路线设置如下：

Route::group(['domain' => '{sub}.example.com', 'namespace' => 'Controllers\Admin'], function()
{
    Route::get('/', function(){ return Redirect::to('/dashboard'); });

    Route::any('{all}', function($uri){ return Redirect::to('/404'); })->where('all', '.*');

})->where('sub', 'local.admin');

当我添加->where时，它只是给我一个错误：

Call to a member function where() on a non-object

基本上我只是希望在域中捕获admin的任何内容并将其转到该路由组。我知道我可以通过一些if语句来做到这一点，但对于我来说，与团队一起做这件事似乎更清晰。或者if陈述是要走的路？

Answer 1

您应该在组内的路由元素上调用where函数。如果您只想获得特定的子域，则无需添加变量，只需将其添加到组函数中即可。

Route::group(['domain' => '{sub}.example.com', 'namespace' => 'Controllers\Admin'], function()
{
    Route::get('/', function(){ return Redirect::to('/dashboard'); })->where('sub', 'local.admin');
    Route::any('{all}', function($uri){ return Redirect::to('/404'); })->where('all', '.*')->where('sub', 'local.admin');
});

OR

Route::group(['domain' => 'local.admin.example.com', 'namespace' => 'Controllers\Admin'], function()
{
    Route::get('/', function(){ return Redirect::to('/dashboard'); });
    Route::any('{all}', function($uri){ return Redirect::to('/404'); })->where('all', '.*');
});

Answer 2

试一试：

Route::domain('{estado}.venezuela.gob.ve')->group(function () {
  Route::get('/', 'EstadoController@index')->where('estado', 'distrito-capital|amazonas|anzoategui|apure|aragua|barinas|bolivar|carabobo|cojedes|delta-amacuro|falcon|guarico|lara|merida|miranda|monagas|nueva-esparta|portuguesa|sucre|tachira|trujillo|vargas|yaracuy|zulia|federales-federales');
  Route::get('/Otro', 'EstadoController@index')->where('estado', 'distrito-capital|amazonas|anzoategui|apure|aragua|barinas|bolivar|carabobo|cojedes|delta-amacuro|falcon|guarico|lara|merida|miranda|monagas|nueva-esparta|portuguesa|sucre|tachira|trujillo|vargas|yaracuy|zulia|federales-federales');
});

Route::domain('venezuela.gob.ve')->group(function () {
  Route::get('/', 'NacionController@index');
  Route::get('/Otro', 'NacionController@index');
});
// Another universal route
Route::get('/algo', function () {
    return "algo";
});

请求通配符值的一个很好的做法可能就是：

州控制员：

    namespace Venezuela\Http\Controllers;

    use Illuminate\Http\Request;
    use Venezuela\EstadosModel;

    class EstadoController extends Controller {
        public $estado;
        public $estado_actual;
        public function __construct(Request $request)
        {
            $this->estado = $request->estado;
            // Global process for all States request
            $this->estado_actual = EstadosModel::where('slug', $this->estado)->first();
        }

        public function index($estado) {
            // return view('estado.portada', ['estado' => $estado, 'estado_actual' => $this->estado_actual]);
            return 'index for: '.$estado;
        }

        public function otro($estado) {
            // return view('estado.otro', ['estado' => $estado, 'estado_actual' => $this->estado_actual]);
            return 'other action for: '.$estado;
        }

    }

国家财产管理员：

    <?php

    namespace Venezuela\Http\Controllers;

    use Illuminate\Http\Request;

    class NacionController extends Controller {


        public function index() {
            // return view('nacion.portada');
            return 'index';
        }

        public function otro() {
            // return view('nacion.otro');
            return 'other action';
        }
    }

结果：

http://venezuela.gob.ve -> index
http://venezuela.gob.ve/Otro -> other action
http://venezuela.gob.ve/algo -> algo
http://lara.venezuela.gob.ve -> index for: lara
http://lara.venezuela.gob.ve/Otro -> Other for: lara
http://lara.venezuela.gob.ve/algo -> algo
http://yaracuy.venezuela.gob.ve -> index for: yaracuy
http://yaracuy.venezuela.gob.ve/Otro -> Other for: yaracuy
http://yaracuy.venezuela.gob.ve/algo -> algo
http://another.venezuela.gob.ve -> 404
http://another.venezuela.gob.ve/Otro -> 404
http://another.venezuela.gob.ve/algo -> algo

Laravel如何过滤通配符子域？

2 个答案: