您好我在JSON格式的Web API中获得了下一个结果:
[
{
"$id":"47",
"CodISO":"BIH",
"ES":"Bosnia y Herzegovina",
"EN":"Bosnia and Herzegovina"
},
{
"$id":"48",
"CodISO":"BLR",
"ES":"Bielorrusia",
"EN":"Belarus"
},
{
"$id":"49",
"CodISO":"BLZ",
"ES":"Belice",
"EN":"Belize"
},
{
"$id":"50",
"CodISO":"BOL",
"ES":"Bolivia",
"EN":"Bolivia"
},
{
"$id":"51",
"CodISO":"BON",
"ES":"Bonaire",
"EN":"Bonaire"
},
{
"$id":"52",
"CodISO":"BOT",
"ES":"Botsuana",
"EN":"Botswana"
},
{
"$id":"53",
"CodISO":"BRA",
"ES":"Brasil",
"EN":"Brazil"
},
{
"$id":"54",
"CodISO":"BRB",
"ES":"Barbados",
"EN":"Barbados"
}
]
现在,我想要阅读项目' ES'其中item' CodISO'的价值=' BOL'在Delphi SuperObject中,我无法找到解决方案,花了一整天的时间来尝试它。
我不知道如何使用Embarcadero TJSONValue
,TJSONObject
,TJSONArray
迭代SuperObject元素。我是SuperObject的新手:
var
json: ISuperObject;
Retriever: TIdHTTP;
Url: string;
AnsiStr: AnsiString;
begin
URL := Form1.RestClient1.BaseURL;
try
Retriever := TIdHTTP.Create(nil);
try
AnsiStr := Retriever.Get(Url);
json := SO(AnsiStr);
{ Here code to iterate with json elements in SuperObject.......
.
.
.
.
}
finally
Retriever.Free;
end;
except
on E: Exception do
ShowMessage(E.ClassName + ': ' + E.Message);
end;
End;
答案 0 :(得分:1)
正如Rufo爵士所说,你需要阅读SuperObject documentation。
尝试这样的事情:
var
JsonArr, JsonObj: ISuperObject;
Retriever: TIdHTTP;
Url, JsonStr, ES: string;
I: Integer;
begin
URL := Form1.RestClient1.BaseURL;
try
Retriever := TIdHTTP.Create(nil);
try
JsonStr := Retriever.Get(Url);
finally
Retriever.Free;
end;
JsonArr := SO(JsonStr).AsArray;
for I := 0 to JsonArr.Length-1 do
begin
JsonObj := JsonArr.O[I];
if JsonObj.S['CodISO'] = 'BOL' then
begin
ES := JsonObj.S['ES'];
Break;
end;
end;
except
on E: Exception do
ShowMessage(E.ClassName + ': ' + E.Message);
end;
end;