伙计们,我一直试图将矩阵的最后一个值作为第一个,第一个值作为第二个,但这是我的出来
生成矩阵es:
8, 4, 10,
4, 6, 9,
3, 9, 7,
颠倒矩阵: 7,9,3,7,9,3,7,9,3,
这是代码:
public String segmat(int a[][]) {
String s = "";
for (int i =0;i<a.length;i++){
//for (int i = a.length - 1; i >= 0; i--) {
for (int j = a[0].length - 1; j >= 0; j--) {
s += a[a.length - 1][j] + ", ";
}
}
return s;
}
答案 0 :(得分:0)
此示例对您有所帮助
我对代码进行了评论,因此很容易理解
public class MatrixExample {
private static int[][] reverse(int[][] matrix){
int row=matrix.length;
int column=matrix[0].length; //we have for shure this element, his length is the number of colmn
int to_return[][] = new int[row][column]; //this is a matrix of the same dimention of the original
//the indexes that will cicle the row and the column of the new matrix
int new_row=0;
int new_column=0;
for(int i=row-1;i>-1;i--){ //this will cile the rows from the last to thee first
for(int j=column-1;j>-1;j--){ //this will cicle the colums from the last to the first
to_return[new_row][new_column]=matrix[i][j];
new_column++;
}
new_column=0;
new_row++;
}
return to_return;
}
public static void main(String[] args) {
int matrix[][] = {{ 1, 2, 3},
{4, 5, 6},
{7, 8, 9},
{10,11,12}};
int[][] new_matrix = reverse(matrix);
for(int i=0;i<new_matrix.length;i++){
for(int j=0;j<new_matrix[0].length;j++){
System.out.print(new_matrix[i][j]+" ");
}
System.out.println();
}
}
}