Question

如何使第二个标签上的后退和下一个按钮有效？（后退按钮转到选项卡1，然后下一个按钮转到选项卡3）。下面是我的代码..我知道这个问题之前已经被问过并回答了，但是我对jQuery并不是很熟悉，只是从http://inspirationalpixels.com/tutorials/creating-tabs-with-html-css-and-jquery#step-jquery复制了代码。

jQuery(document).ready(function() {
    jQuery('.tabs .tab-links a').on('click', function(e)  {
        var currentAttrValue = jQuery(this).attr('href');
 
        // Show/Hide Tabs
        jQuery('.tabs ' + currentAttrValue).show().siblings().hide();
 
        // Change/remove current tab to active
        jQuery(this).parent('li').addClass('active').siblings().removeClass('active');
 
        e.preventDefault();
    });
});

/*----- Tabs -----*/
.tabs {
    width:100%;
    display:inline-block;
}
 
    /*----- Tab Links -----*/
    /* Clearfix */
    .tab-links:after {
        display:block;
        clear:both;
        content:'';
    }
 
    .tab-links li {
        margin:0px 5px;
        float:left;
        list-style:none;
    }
 
        .tab-links a {
            padding:9px 15px;
            display:inline-block;
            border-radius:3px 3px 0px 0px;
            background:#7FB5DA;
            font-size:16px;
            font-weight:600;
            color:#4c4c4c;
            transition:all linear 0.15s;
        }
 
        .tab-links a:hover {
            background:#a7cce5;
            text-decoration:none;
        }
 
    li.active a, li.active a:hover {
        background:#CCCCCC;
        color:#4c4c4c;
    }
 
    /*----- Content of Tabs -----*/
    .tab-content {
        padding:15px;
        border-radius:3px;
        box-shadow:-1px 1px 1px rgba(0,0,0,0.15);
        background:#CCCCCC;
    }
 
        .tab {
            display:none;
        }
 
        .tab.active {
            display:block;
        }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="tabs">
    <ul class="tab-links">
        <li class="active"><a href="#tab1">Tab #1</a></li>
        <li><a href="#tab2">Tab #2</a></li>
        <li><a href="#tab3">Tab #3</a></li>
        <li><a href="#tab4">Tab #4</a></li>
    </ul>
 
    <div class="tab-content">
        <div id="tab1" class="tab active">
            <p>Tab #1 content goes here!</p>
            <p>Donec pulvinar neque sed semper lacinia. Curabitur lacinia ullamcorper nibh; quis imperdiet velit eleifend ac. Donec blandit mauris eget aliquet lacinia! Donec pulvinar massa interdum risus ornare mollis.</p>
        </div>
 
        <div id="tab2" class="tab">
          <a href="#back_tab1"><input type="button" value="Back" id="recipBackButton"></a>
		  <a href="#next_tab3"><input type="button" value="Next" id="recipNextButton"></a><br>
            <p>Tab #2 content goes here!</p>
            <p>Donec pulvinar neque sed semper lacinia. Curabitur lacinia ullamcorper nibh; quis imperdiet velit eleifend ac. Donec blandit mauris eget aliquet lacinia! Donec pulvinar massa interdum risus ornare mollis. In hac habitasse platea dictumst. Ut euismod tempus hendrerit. Morbi ut adipiscing nisi. Etiam rutrum sodales gravida! Aliquam tellus orci, iaculis vel.</p>
        </div>
 
        <div id="tab3" class="tab">
            <p>Tab #3 content goes here!</p>
            <p>Donec pulvinar neque sed semper lacinia. Curabitur lacinia ullamcorper nibh; quis imperdiet velit eleifend ac. Donec blandit mauris eget aliquet lacinia! Donec pulvinar massa interdum ri.</p>
        </div>
 
        <div id="tab4" class="tab">
            <p>Tab #4 content goes here!</p>
            <p>Donec pulvinar neque sed semper lacinia. Curabitur lacinia ullamcorper nibh; quis imperdiet velit eleifend ac. Donec blandit mauris eget aliquet lacinia! Donec pulvinar massa interdum risus ornare mollis. In hac habitasse platea dictumst. Ut euismod tempus hendrerit. Morbi ut adipiscing nisi. Etiam rutrum sodales gravida! Aliquam tellus orci, iaculis vel.</p>
        </div>
    </div>
</div>

Answer 1

这应该有效

 jQuery('#recipNextButton').on('click', function() {

   var $activeTab = $('.tab-links li.active');
   var $wrapper = jQuery(this).closest('.tabs');
   var indexActive = $wrapper.find('li.active').index();

   $wrapper.find('li').eq(indexActive + 1).find('a').click();
});

jQuery('#recipBackButton').on('click', function() {

   var $activeTab = $('.tab-links li.active');
   var $wrapper = jQuery(this).closest('.tabs');
   var indexActive = $wrapper.find('li.active').index();

   $wrapper.find('li').eq(indexActive - 1).find('a').click();
});

请在此处查看：演示 http://jsfiddle.net/R5PXH/474/

下一步＆amp; Jquery选项卡的后退按钮

1 个答案: