Question

我需要在我的脚本中添加一个获取当前服务器时间的函数。

我使用下面的PHP文件以毫秒为单位获取服务器时间。

<?php
date_default_timezone_set('Europe/London');
$serverTime = round(microtime(true) * 1000);
echo json_encode($serverTime);
?>

然后我想添加一个Ajax请求来获取＆＃39; serverTime.PHP并将其放入变量中，以便我可以计算出某些内容正确结束之前的时间。

我目前通过使用此

获得客户时间

var now   = new Date ().getTime();

现在我要删除该行并添加我的ajax请求。

我尝试将以下代码添加到脚本中但我无法执行

function now ()
{
    this.ajax.open('GET', 'serverTime.php',
                   true);
    this.ajax.send(null);       

    if (this.ajax.readyState != 4) return;
    if (this.ajax.status == 200)
    {
        // get response
        var now = eval ('('+this.ajax.responseText+')');
    }
}

最终结果是变量＆＃39; NOW＆＃39;包含serverTime.PHP的输出

这是我的脚本，我试图以各种方式添加anothert ajax get请求，但我无法使其正常运行。

$.ajaxSetup({
    type: 'GET',
    headers: { "cache-control" : "no-cache" }
});

var PlayList = function (onUpdate, onError)
{
    // store user callbacks
    this.onUpdate = onUpdate; 
    this.onError  = onError;

    // setup internal event handlers
    this.onSongEnd = onSongEnd.bind (this);

    // allocate an Ajax handler
    try
    {
        this.ajax = window.XMLHttpRequest
            ? new XMLHttpRequest()
            : new ActiveXObject("Microsoft.XMLHTTP");
    }
    catch (e)
    {
        // fatal error: could not get an Ajax handler
        this.onError ("could not allocated Ajax handler");
    }
    this.ajax.onreadystatechange = onAjaxUpdate.bind(this);

    // launch initial request
    this.onSongEnd ();

    // ------------------------------------------
    // interface
    // ------------------------------------------

    // try another refresh in the specified amount of seconds
    this.retry = function (delay)
    {
        setTimeout (this.onSongEnd, delay*5000);
    }

    // ------------------------------------------
    // ancillary functions
    // ------------------------------------------

    // called when it's time to refresh the playlist
    function onSongEnd ()
    {
        // ask for a playlist update
        this.ajax.open('GET', 'playlist.php', // <-- reference your PHP script here
                       true);
        this.ajax.send(null);       
    }

    // called to handle Ajax request progress
    function onAjaxUpdate ()
    {       
        if (this.ajax.readyState != 4) return;
        if (this.ajax.status == 200)
        {
            // get response
            var list = eval ('('+this.ajax.responseText+')');

            // compute milliseconds remaining till the end of the current song
            var start = new Date(list[0].date_played.replace(' ', 'T')).getTime();  
            var now   = new Date (                                    ).getTime();
            var d = start - now + 6500
                  + parseInt(list[0].duration);
            if (d < 0)

            {
                // no new song started, retry in 3 seconds
                d = 3000;
            }
            else
            {
                // notify caller
                this.onUpdate (list);
            }

            // schedule next refresh
            setTimeout (this.onSongEnd, d);

        }
        else
        {
            // Ajax request failed. Most likely a fatal error
            this.onError ("Ajax request failed");
        }       
    }
}

var list = new PlayList (playlistupdate, playlisterror);

function playlistupdate (list)
{
for (var i = 0 ; i != list.length ; i++)
    {
        var song = list[i];

    }
{

    document.getElementById("list0artist").innerHTML=list[0].artist;
    document.getElementById("list0title").innerHTML=list[0].title;
    document.getElementById("list0label").innerHTML=list[0].label;
    document.getElementById("list0albumyear").innerHTML=list[0].albumyear;
    document.getElementById("list0picture").innerHTML='<img src="/testsite/covers/' + list[0].picture + '" width="170" height="170"/>';

    document.getElementById("list1artist").innerHTML=list[1].artist;
    document.getElementById("list1title").innerHTML=list[1].title;
    document.getElementById("list1label").innerHTML=list[1].label;
    document.getElementById("list1albumyear").innerHTML=list[1].albumyear;
    document.getElementById("list1picture").innerHTML='<img src="/testsite/covers/' + list[1].picture + '" width="84" height="84"/>';

    document.getElementById("list2artist").innerHTML=list[2].artist;
    document.getElementById("list2title").innerHTML=list[2].title;
    document.getElementById("list2label").innerHTML=list[2].label;
    document.getElementById("list2albumyear").innerHTML=list[2].albumyear;
    document.getElementById("list2picture").innerHTML='<img src="/testsite/covers/' + list[2].picture + '" width="84" height="84"/>';

    document.getElementById("list3artist").innerHTML=list[3].artist;
    document.getElementById("list3title").innerHTML=list[3].title;
    document.getElementById("list3label").innerHTML=list[3].label;
    document.getElementById("list3albumyear").innerHTML=list[3].albumyear;
    document.getElementById("list3picture").innerHTML='<img src="/testsite/covers/' + list[3].picture + '" width="84" height="84"/>';

    document.getElementById("list4artist").innerHTML=list[4].artist;
    document.getElementById("list4title").innerHTML=list[4].title;
    document.getElementById("list4label").innerHTML=list[4].label;
    document.getElementById("list4albumyear").innerHTML=list[4].albumyear;
    document.getElementById("list4picture").innerHTML='<img src="/testsite/covers/' + list[4].picture + '" width="84" height="84"/>';

$('.nowPlayNoAnimate').each(function() {
    $(this).toggleClass('nowPlayAnimate', $(this).parent().width() < $(this).width());
});

}
}

function playlisterror (msg)
{
    // display error message
    console.log ("Ajax error: "+msg);

    //retry
    list.retry (10); // retry in 10 seconds
}

Answer 1

为什么不使用jquery方法？

function getServerTime() {
  var now = null; 
  $.ajax({
    url: "serverTime.php",
    dataType: 'JSON',
    async: false,
    success: function (data) {
      now = data;
    }
  });
  return now;
}

您可以通过浏览器移植方式启动任意数量的请求。

PS：你可能也想替换 document.getElementById("list4artist").innerHTML=list[4].artist;

更短 $("#list4artist").html(list[4].artist);

编辑：添加async参数以使执行等待ajax调用以模拟非异步函数调用。

Answer 2

假设您的服务返回日期对象，您需要在成功函数中添加以下行（由ClémentPrévost建议）：

var now = data;

成功函数是服务器返回值后触发器的异步回调函数。您应该阅读有关Jquery Ajax的内容，它将使您的生活更轻松。

向脚本添加多个AJAX调用

2 个答案: