Question

我使用以下例外：

class MyApplicationPaymentError(Exception):
    pass

但是，我希望能够将status_code和error_message传递给它。所以我可以做到以下几点：

try:
    payment.validate()
except MyApplicationPaymentError:
    print '!!!', status_code, error_message

如何修改Exception，然后修改View代码以完成上述操作？

Answer 1

>>> class MyApplicationPaymentError(Exception):
...   def __init__(self, statuscode, errormessage):
...     self.statuscode = statuscode
...     self.errormessage = errormessage
... 
>>> try:
...   raise MyApplicationPaymentError(418, "I'm a Teapot")
... except MyApplicationPaymentError as e:
...   print(e.statuscode, e.errormessage)
... 
418 I'm a Teapot

如何在Exception中传递status_code，error_message

1 个答案: