Question

我对php页面的背景颜色变化有问题。首先，我想从DATABASE中获取颜色名称以使当前颜色不变。我的意思是，如果用户将背景颜色更改为BLUE，例如，它将是常量和永久性的。所以，我将颜色存储在数据库中，但问题是我无法根据用户选择的颜色更新数据库。

这是数据库中的当前颜色（这部分工作很好，我只是为了让一切易于理解而添加了这一部分）;

<body name="body" id="body" bgcolor="

<?php 
         mysql_connect("localhost","DB","password") or die("ERROR!!");
         mysql_select_db("DB") or die("COULDN'T FIND IT!!") or die("COULDN'T FIND DB"); 


        $sql = mysql_query("SELECT color FROM background");

        $color = 'color';   

        while($rows = mysql_fetch_assoc($sql))
        echo $rows[color];

?>

">

这是我更新数据库的一部分;

<?php

        $con = mysql_connect("localhost","DB","password") or die("ERROR!!");
        mysql_select_db("DB") or die("COULDN'T FIND IT!!") or die("COULDN'T FIND DB"); 


            if (isset( $_SESSION['CurrentUser'])){

            echo '<form method="post"><center><input type="submit" name="background" value="Change background">';
            echo '<input type="submit" name="color" value="Change font color">';
            echo '<input type="submit" name="size" value="Change font size"></center></form><br/>'; 

                if (isset( $_POST['background'])){ 

                echo '<span style="color:black"><center>Choose background color</center></span><br/>';
                echo '<center><a href="?colour=blue"><img src="blue.png" width="20" height="50"></a></center>'; 
                echo '<center><a href="?colour=black"><img src="black.jpg" width="20" height="50"></a></center>'; 
                echo '<center><a href="?colour=silver"><img src="silver.jpg" width="20" height="50"></a></center>';
                echo '<center><a href="?colour=red"><img src="red.png" width="20" height="50"></a></center><br/><br/>';

                $Color = $_POST['colour'];  // THIS LINE IS THE PROBLEM

                if ($Color == 'blue'){
                $sql = "UPDATE background SET color='blue' WHERE id=1";
                mysql_query($sql,$con); }
                if ($Color == 'black'){
                $sql = "UPDATE background SET color='black' WHERE id=1";
                mysql_query($sql,$con); }
                if ($Color == 'silver'){
                $sql = "UPDATE background SET color='silver' WHERE id=1";
                mysql_query($sql,$con); }
                if ($Color == 'red'){
                $sql = "UPDATE background SET color='red' WHERE id=1";
                mysql_query($sql,$con); }
                }

    }
    ?>

    </form>


    </td></tr></table>

一切都运作得好！我的意思是如果我想要更新数据库，那么就没有与MYSQL连接或其相关的问题。问题是我无法获得“颜色”参数的值来更新数据库。

感谢

Answer 1

当您回显结果时，您在color之前忘记了一个美元符号：

$color = 'color';
while($rows = mysql_fetch_assoc($sql))
    echo $rows[color];

应该是：

$color = 'color';
while($rows = mysql_fetch_assoc($sql))
    echo $rows[$color];

Answer 2

How about this:

//....

    echo '<form method="post"><center><input type="submit" name="background" value="Change background">';
    echo '<input type="submit" name="color" value="Change font color">';
    echo '<input type="submit" name="size" value="Change font size"></center></form><br/>'; 

    if (isset( $_POST['background'])){ 

        echo '<span style="color:black"><center>Choose background color</center></span><br/>';
        echo '<center><a href="?colour=blue"><img src="blue.png" width="20" height="50"></a></center>'; 
        echo '<center><a href="?colour=black"><img src="black.jpg" width="20" height="50"></a></center>'; 
        echo '<center><a href="?colour=silver"><img src="silver.jpg" width="20" height="50"></a></center>';
        echo '<center><a href="?colour=red"><img src="red.png" width="20" height="50"></a></center><br/><br/>';

   }

   if( !empty( $_GET['colour'] )) {
        $Color = $_GET['colour'];

        if ($Color == 'blue'){
                $sql = "UPDATE background SET color='blue' WHERE id=1";
                mysql_query($sql,$con); }
        if ($Color == 'black'){
                $sql = "UPDATE background SET color='black' WHERE id=1";
                mysql_query($sql,$con); }
        if ($Color == 'silver'){
                $sql = "UPDATE background SET color='silver' WHERE id=1";
                mysql_query($sql,$con); }
        if ($Color == 'red'){
                $sql = "UPDATE background SET color='red' WHERE id=1";
                mysql_query($sql,$con); }
        }    
   }
    ?>

    </form>

Answer 3

然后尝试

        $Color = $_GET['colour'];

用php改变背景颜色

3 个答案: