Question

我有一个表单，我需要验证经度和纬度字段。

以下代码适用于捕获keypress。但是在focusout部分，有两个问题我无法弄清楚：

1 /它应该取代＆＃34;不允许＆＃34;带有＆＃39;＆＃39;的字段中的字符，不会发生

2 /警报永远不会被触发

代码如下所示：

    var allowedLongLat = "0123456789.-";

    $("#latitude").keypress( function(e) {
        var chr = String.fromCharCode(e.which);
        if (allowedLongLat.indexOf(chr) < 0)
        {
            alert("The character "+chr+" is not allowed in this field!");
            return false;
        }
    });
    $(document).on("focusout","#latitude",function(){
        var str = $("#latitude").val();
        var wrongchars = [];
        var wrongalert = "";
        for (var i = 0, len = str.length; i < len; i++) {
            if (allowedLongLat.indexOf(str[i]) < 0)
            {
                wrongchars.push(str[i]);
            }
        }
        jQuery.each(wrongchars , function(index, value){
             $("#latitude").val( str.replace(\'/\'+value+\'/g\', \'\') );
             wrongalert += value;
        });                 
        if ( wrongalert.lenght > 1 )
        {
            alert("The characters "+wrongalert+" are not allowed in this field!");
        }
    });

我错过了哪些想法？

Answer 1

在代码中发现了一些错误

$("#latitude").val( str.replace(\'/\'+value+\'/g\', \'\') );

有一些拼写错误，

if ( wrongalert.lenght > 1 )

错字错误，应该是长度。

我做了this jsfiddle。

var allowedLongLat = "0123456789.-";

$(document).on("focusout","#latitude",function(){
    var str = $("#latitude").val();
    var wrongchars = [];
    var wrongalert = "";
    for (var i = 0, len = str.length; i < len; i++) {
        if (allowedLongLat.indexOf(str[i]) < 0)
        {
            wrongchars.push(str[i]);
        }
    }
    //console.log(wrongchars);
    jQuery.each(wrongchars , function(index, value){
        console.log(value);
         $("#latitude").val( $("#latitude").val().replace(value, '') ); // I simplified here
         wrongalert += value;
    });     
    if ( wrongalert.length > 1 )// here was typo error
    {
        alert("The characters "+wrongalert+" are not allowed in this field!");
    }
});

从字符串中查找和删除不合规的字符

1 个答案: