Question

我对Python完全陌生，但令我惊讶的是，我已经制作了这段代码：

if __name__ == "__main__":
with open("wordlist.txt") as infile:
    for line in infile:
        print(line)    



with open ("cv000_29416.txt", "r") as myfile:
   data=myfile.read().replace('\n', '')
print (data.count("bad"))

关键是，我想计算cv000_29416.txt中wordlist.txt中的单词。

（所以wordlist.txt包含例如二十个单词，如＆＃39; bad＆＃39;，＆＃39; good＆＃39; etcetera，cv000_29416.txt是一个长文本，我想计算多少时间＆＃39;坏＆＃39;，＆＃39;好＆＃39;等等在cv000_29416.txt中出现

我可以在秒段代码中插入某个地方吗？

谢谢！抱歉英语不好

Answer 1

# create a collection of the words that want to count
with open('wordlist.txt') as infile:
    counts = {}
    for line in infile:
        for word in line.split():
            counts[word] = 0

# increment the count of the words that you really care about
with open("cv000_29416.txt") as infile:
    for line in infile:
        for word in line.split():
            if word in counts:
                counts[word] += 1

for word,count in counts.items():
    print(word, "appeared", count, "times")

Answer 2

使用collections.Counter dict计算所有单词：

from collections import Counter
with open ("cv000_29416.txt", "r") as myfile:
   data = Counter(myfile.read().split())
print (data["bad"])

要把它放在一起，假设每个单词在wordlist.txt中单独一行：

from collections import Counter
with open ("cv000_29416.txt", "r") as myfile,open("wordlist.txt") as infile:
    data = Counter(myfile.read().split())
    for line in infile:
        print(data.get(line.rstrip(),0))

在Python中计算文件中的单词

2 个答案: