MySql搜索查询无法返回包含％20的行

Question

我的数据库查询有问题。当我尝试先将空格转换为％20的行时，查询返回null。我测试了其他行正常工作，为什么会出现这个问题？我是否需要从每一行手动删除％20以使其正常工作？

谢谢！

<?php

include_once 'includes/db_connect.php';

$query = "SELECT * FROM USERS WHERE LIKES= '$_GET[imgname]' ";

//Creating resonse json array, with another array inside
$jsonResponse = array( "info" =>array() );

if($result = mysqli_query($mysqli, $query)) {
    while($row = mysqli_fetch_assoc($result)){

     $jsonRow = array(        

         'names'            =>      $row['USERNAME'],
         'userIds'          =>      $row['USERID']   

        );          

        //adding the $jsonRow array to the end of the "users" array as key/value
        array_push($jsonResponse["info"], $jsonRow);
    }   

}
    //encoding to json for the app
    echo json_encode($jsonResponse);



?>

Answer 1

将您的SQL查询更改为：

$query = "SELECT * FROM USERS WHERE LIKES= '".rawurlencode($_GET[imgname])."' ";

LIKES列已对图像路径进行编码（空间转换为%20）。因此，$_GET[imgname]应编码为与数据库记录匹配。