是否可以在没有任何游戏引擎的情况下简单地在java（swing）中进行360度移动？我只有这个尝试：
public class Game extends JPanel implements Runnable {
int x = 300;
int y = 500;
float angle = 30;
Game game;
public static void main(String[] args) {
JFrame frame = new JFrame();
frame.add(new Game());
frame.setSize(600, 600);
frame.setVisible(true);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
public Game() {
setSize(600, 600);
Thread thread = new Thread(this);
thread.start();
}
@Override
public void paint(Graphics g) {
g.setColor(Color.WHITE);
g.drawRect(0, 0, 600, 600);
g.setColor(Color.CYAN);
g.fillOval(x, y, 10, 10);
g.dispose();
}
@Override
public void run() {
while(true) {
angle += -0.1;
x += Math.sin(angle);
y--;
repaint();
try {
Thread.sleep(50);
} catch (InterruptedException ex) {}
}
}
}
如下图所示，我不知道如何处理旋转运动，这是输出：
答案 0 :(得分：3)
实际上，这很有可能。
我首选的方法是实际利用Graphics转换，这样您就不必进行任何计算，而是全部留给Graphics
顺便说一下：
Graphics对象，因此请勿对其进行处理。 paintComponent()而不是paint() super.paintComponent() 小演示示例：
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Shape;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.geom.AffineTransform;
import java.awt.geom.Area;
import java.awt.geom.RoundRectangle2D;
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
import javax.swing.JComponent;
import javax.swing.JFrame;
import javax.swing.SwingUtilities;
import javax.swing.Timer;
public class TestRotate {
public static class ShapeAndColor {
private final Shape shape;
private final Color color;
public ShapeAndColor(Shape shape, Color color) {
super();
this.shape = shape;
this.color = color;
}
public Shape getShape() {
return shape;
}
public Color getColor() {
return color;
}
}
public static class RotatingShapesPanel extends JComponent {
private List<ShapeAndColor> shapes;
private double rotation = 0.0;
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g;
AffineTransform translate = AffineTransform.getTranslateInstance(-getWidth() / 2, -getHeight() / 2);
AffineTransform rotate = AffineTransform.getRotateInstance(rotation);
AffineTransform t = AffineTransform.getTranslateInstance(getWidth() / 2, getHeight() / 2);
t.concatenate(rotate);
t.concatenate(translate);
g2d.setTransform(t);
AffineTransform scale = AffineTransform.getScaleInstance(getWidth(), getHeight());
for (ShapeAndColor shape : shapes) {
Area area = new Area(shape.getShape());
g2d.setColor(shape.getColor());
area.transform(scale);
g2d.fill(area);
}
}
public void setShapes(List<ShapeAndColor> shapes) {
this.shapes = shapes;
repaint();
}
public double getRotation() {
return rotation;
}
public void setRotation(double rotation) {
this.rotation = rotation;
repaint();
}
}
protected void initUI(final boolean useBorderLayout) {
final JFrame frame = new JFrame();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
List<ShapeAndColor> shapes = new ArrayList<>();
Random r = new Random();
for (int i = 0; i < 10; i++) {
double x = r.nextDouble();
double y = r.nextDouble();
double w = r.nextDouble();
double h = r.nextDouble();
w = Math.min(w, 1 - x) / 2;
h = Math.min(h, 1 - y) / 2;
double a = Math.min(w, h) / 10.0;
RoundRectangle2D.Double shape = new RoundRectangle2D.Double(x, y, w, h, a, a);
Color color = new Color(r.nextInt(256), r.nextInt(256), r.nextInt(256));
shapes.add(new ShapeAndColor(shape, color));
}
final RotatingShapesPanel panel = new RotatingShapesPanel();
panel.setShapes(shapes);
frame.add(panel);
frame.setSize(600, 600);
frame.setVisible(true);
Timer t = new Timer(0, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
double rotation = panel.getRotation() + 0.02;
if (rotation > Math.PI * 2) {
rotation -= Math.PI * 2;
}
panel.setRotation(rotation);
}
});
t.setRepeats(true);
t.setDelay(10);
t.start();
}
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
new TestRotate().initUI(true);
}
});
}
}
答案 1 :(得分：0)
改变几行......
int basex = 300; // midpoint of the circle
int basey = 400;
int radius = 100; // radius
int x;
int y;
float angle = 0; // Angles in radians, NOT degrees!
public void run() {
while(true) {
angle += 0.01;
x = (int)(basex + radius*Math.cos(angle));
y = (int)(basey - radius*Math.sin(angle));
repaint();
try {
Thread.sleep(50);
} catch (InterruptedException ex) {}
}
}
不确定你在那里尝试编码，但这是圆形运动的正确公式。
答案 2 :(得分：0)
你的程序存在一些问题：
int x = 300;
int y = 500;
您应该使用像double这样的浮点数据类型来存储坐标。当您想要绘制它们时，可以将它们强制转换为int。如果将它们存储在int中，则会失去精确度。
x += Math.sin(angle);
y--;
这不起作用，因为y递减而不是使用Math.sin(angle)计算。 （我们为Math.cos）x
这是你的固定代码（省略了未更改的部分）：
double x = 300;
double y = 500;
float angle = 30;
double radius = 10D; // new variable to increase the radius of the drawn circle
Game game;
// main method
// constructor
@Override
public void paint(Graphics g) {
// ... stuff omitted
g.fillOval((int)x, (int)y, 10, 10); // you can cast to int here
g.dispose();
}
@Override
public void run() {
while (true) {
angle -= 0.1; // is the same as `angle += -0.1`
x += radius * Math.cos(angle);
y += radius * Math.sin(angle);
repaint();
// ... try catch block
}
}
此电流逆时针绘制圆圈。如果要顺时针绘制它，请将角度更改为：
angle += 0.1;
答案 3 :(得分：0)
要计算一个点周围的旋转，你需要一个旋转中心点（cx，cy），该点与中心的半径或距离，你需要角度（弧度，而不是度数），你需要使用正弦和余弦来计算点绕中心旋转时点的偏移量。
int cx, cy, radius; // I'll let you determine these
double theta = Math.toRadians(30);
double dtheta = Math.toRadians(-0.1);
double dx = Math.cos(theta) * radius;
double dy = Math.sin(theta) * radius;
int x = (int)(cx + dx);
int y = (int)(cy + dy);
repaint();
theta += dtheta; // step the angle