Question

我想分割日期和时间字符串。我有两种格式：MM / DD / YYYY HH：MM：SS AM和MM / DD / YYYY

当爆炸阵列时间值不存在时，我不断收到错误。如果没有值，我希望它默认为凌晨12:00:00。

<?php
        $date = array('10/6/2014 10:00:00 AM','10/10/2014');

        foreach ($date as $date) {
        $date = str_replace(array('/', ' ', ':'),',',$date);

        $split_date = explode(",",$date);

                $month = $split_date[0];
                $day = $split_date[1]; 
                $year = $split_date[2];
                $hour = $split_date[3];
                $minute = $split_date[4];
                $second = $split_date[5];
                $AMPM = $split_date[6];

        echo $month;
        echo "<br />";
        echo $day;
        echo "<br />";
        echo $year;
        echo "<br />";
        echo $hour;
        echo "<br />";
        echo $minute;
        echo "<br />";
        echo $second;
        echo "<br />";
        echo $AMPM;
        echo "<br />";echo "<br />";
        }

＆GT;

Answer 1

使用此代码，您将不会收到错误

$month = isset($split_date[0]) ? $split_date[0] : '';
$day = isset($split_date[1]) ? $split_date[1] : '';
$year = isset($split_date[2]) ? $split_date[2] : '';
$hour = isset($split_date[3]) ? $split_date[3] : '';
$minute = isset($split_date[4]) ? $split_date[4] : '';
$second = isset($split_date[5]) ? $split_date[5] : '';
$AMPM = isset($split_date[6]) ? $split_date[6] : '';

Answer 2

这应该可以让您获得单独的值：

<?php

    $dates = array('10/6/2014 10:00:00 AM','10/10/2014');
    $split = preg_split('/([\/: X])/', implode(" ", $dates));
    print_r($split);


?>

输出：

    Array
(
    [0] => 10
    [1] => 6
    [2] => 2014
    [3] => 10
    [4] => 00
    [5] => 00
    [6] => AM
    [7] => 10
    [8] => 10
    [9] => 2014
)

PHP爆炸值不存在

2 个答案: