我有一个#wrapper
div和一个#grid
div嵌套在里面。目前我可以使用下面的这个功能滚动。
getCursorPos : function(){
// set the empty cursor object
var cursor = {};
//get the offset from the left of the grid container
var grid
//offset loop
$(function getCursorPos(){
grid = $('#grid').offset();
setTimeout(getCursorPos, game.loopSpeed);
});
//continuosly get the position
var that = this;
$(document).mousemove(function(e){
//if game mode is menu exit
if(game.mode === 'menu'){
return;
}
// NOTE: this looks a litle over done but don't remove anything
// its like this because javascript uses floating points
// and so in order to line up to the nearest hunderedth I
// had to make the cursor and div position intergers by
// muliplying by ten. one the two are added I reduced them
// and rounded them.
that.x = Math.round(((e.pageX * 10) - (grid.left * 10)) / 10);
that.y = Math.round(((e.pageY * 10) - (grid.top * 10)) / 10);
});
},
问题是鼠标坐标仅在鼠标移动时更新。有没有办法在不移动鼠标的情况下获得坐标?
答案 0 :(得分:0)
您最后一次鼠标移动时始终拥有鼠标的最新最新坐标,请说明这些对您没用的原因。